Math Problem Statement

If f(x) = 5x, what is f^{-1}(x)?

Solution

Given the function f(x)=5xf(x) = 5x, we are asked to find the inverse function f1(x)f^{-1}(x).

To find the inverse of a function, we swap the roles of xx and yy and then solve for yy. Here are the steps:

  1. Start with the original function f(x)=5xf(x) = 5x. Set y=5xy = 5x. y=5xy = 5x
  2. Swap yy and xx (because f1(x)f^{-1}(x) undoes what f(x)f(x) does): x=5yx = 5y
  3. Solve for yy (which will be the inverse function): y=x5=15xy = \frac{x}{5} = \frac{1}{5}x

Thus, the inverse function is f1(x)=15xf^{-1}(x) = \frac{1}{5}x.

The correct answer is: f1(x)=15xf^{-1}(x) = \frac{1}{5}x

Would you like more details on how inverses of functions are derived or have any other questions?

Here are some related questions:

  1. What is the general method for finding the inverse of a linear function?
  2. How do you determine if a function has an inverse?
  3. Can a function be its own inverse? Provide an example.
  4. What is the relationship between a function and its inverse on a graph?
  5. What are the properties of inverse functions in terms of composition?

Tip: To check if two functions are inverses, their compositions should equal the identity function: f(f1(x))=xf(f^{-1}(x)) = x and f1(f(x))=xf^{-1}(f(x)) = x.

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions
Inverse Functions

Formulas

f(x) = 5x
x = 5y
y = \frac{x}{5}

Theorems

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Suitable Grade Level

High School