Math Problem Statement

Suppose a company has fixed costs of $4000 and variable costs per unit of

15

16

x + 1270 dollars,

where x is the total number of units produced. Suppose further that the selling price of its product is

1400 −

1

16

x dollars per unit.

Find the break-even points. (Enter your answers as a comma-separated list.)

Solution

To find the break-even points, we need to set the total costs equal to the total revenue.

Given:

  • Fixed Costs (FC) = $4000
  • Variable Cost per unit (VC) = 15×x16+127015 \times \frac{x}{16} + 1270
  • Selling Price per unit (SP) = 1400116x1400 - \frac{1}{16} x

Total Cost (TC):

The total cost is the sum of fixed and variable costs: TC=FC+(VC×x)=4000+(15×x16+1270)×xTC = FC + (VC \times x) = 4000 + \left(15 \times \frac{x}{16} + 1270\right) \times x

Total Revenue (TR):

Total revenue is given by: TR=SP×x=(1400116x)×xTR = SP \times x = \left(1400 - \frac{1}{16} x\right) \times x

Setting TC equal to TR:

4000+(15×x16+1270)×x=(1400116x)×x4000 + \left(15 \times \frac{x}{16} + 1270\right) \times x = \left(1400 - \frac{1}{16} x\right) \times x

Expanding both sides:

  1. Left Side: TC=4000+(15x16+1270)x=4000+15x216+1270xTC = 4000 + \left(\frac{15x}{16} + 1270\right) x = 4000 + \frac{15x^2}{16} + 1270x

  2. Right Side: TR=(1400116x)x=1400xx216TR = \left(1400 - \frac{1}{16} x\right) x = 1400x - \frac{x^2}{16}

Combining:

4000+15x216+1270x=1400xx2164000 + \frac{15x^2}{16} + 1270x = 1400x - \frac{x^2}{16}

Rearranging:

Combine all terms on one side: 15x216+x216+1270x1400x+4000=0\frac{15x^2}{16} + \frac{x^2}{16} + 1270x - 1400x + 4000 = 0 This simplifies to: 16x216130x+4000=0\frac{16x^2}{16} - 130x + 4000 = 0 x2130x+4000=0x^2 - 130x + 4000 = 0

Solving the Quadratic Equation:

Using the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} where a=1a = 1, b=130b = -130, and c=4000c = 4000.

Calculating the discriminant: b24ac=(130)24×1×4000=1690016000=900b^2 - 4ac = (-130)^2 - 4 \times 1 \times 4000 = 16900 - 16000 = 900

Calculating the roots: x=130±9002x = \frac{130 \pm \sqrt{900}}{2} x=130±302x = \frac{130 \pm 30}{2} This gives us two solutions: x=1602=80andx=1002=50x = \frac{160}{2} = 80 \quad \text{and} \quad x = \frac{100}{2} = 50

Break-even Points:

The break-even points are: 50,80\boxed{50, 80}

If you have any questions or need further details, feel free to ask! Here are some follow-up questions to consider:

  1. How would changes in fixed costs affect the break-even points?
  2. What impact do variable costs have on the overall profitability?
  3. How can the company increase its break-even sales?
  4. What strategies can be implemented if the selling price changes?
  5. How would a decrease in selling price affect the break-even analysis?

Tip: Always analyze how fixed and variable costs interact when assessing profitability!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Break-even Analysis

Formulas

Total Cost (TC) = Fixed Costs + Variable Costs × x
Total Revenue (TR) = Selling Price × x
Quadratic formula x = (-b ± √(b² - 4ac)) / 2a

Theorems

Break-even Point Theorem

Suitable Grade Level

Grades 10-12