Suppose a company has fixed costs of $49,400 and variable cost per unit of 1/3x + 333 dollars, where x is the total number of units produced. Suppose further that the selling price of its product is 2259-2/3x dollars per unit.

In this problem, we are given the fixed and variable costs, as well as the selling price per unit. We can break down the question and set up the necessary equations for total cost, total revenue, and eventually profit, depending on what you're looking to solve.

### Key components of the problem:

1. **Fixed Costs**: These are constant costs that do not depend on the number of units produced, i.e., \$49,400.

2. **Variable Costs per Unit**: This is given as $ \frac{1}{3}x + 333 $ dollars, where $ x $ is the number of units produced.

3. **Selling Price per Unit**: The selling price per unit is $ 2259 - \frac{2}{3}x $.

### Formulas

#### 1. **Total Cost**: 
The total cost $ C(x) $ includes both fixed and variable costs. The variable cost depends on the number of units $ x $ produced.

\[
C(x) = \text{Fixed Cost} + \text{Variable Cost} \cdot x
\]

\[
C(x) = 49,400 + \left( \frac{1}{3}x + 333 \right) \cdot x
\]

Expanding the variable cost part:

\[
C(x) = 49,400 + \left( \frac{1}{3}x^2 + 333x \right)
\]

Thus, the total cost function is:

\[
C(x) = 49,400 + \frac{1}{3}x^2 + 333x
\]

#### 2. **Total Revenue**:
The total revenue $ R(x) $ is the selling price per unit times the number of units produced $ x $:

\[
R(x) = x \cdot \left( 2259 - \frac{2}{3}x \right)
\]

Expanding this:

\[
R(x) = 2259x - \frac{2}{3}x^2
\]

#### 3. **Profit Function**:
The profit function $ P(x) $ is the total revenue minus the total cost:

\[
P(x) = R(x) - C(x)
\]

Substitute $ R(x) $ and $ C(x) $ into this equation:

\[
P(x) = \left( 2259x - \frac{2}{3}x^2 \right) - \left( 49,400 + \frac{1}{3}x^2 + 333x \right)
\]

Simplify the profit function:

\[
P(x) = 2259x - \frac{2}{3}x^2 - 49,400 - \frac{1}{3}x^2 - 333x
\]

Combine like terms:

\[
P(x) = (2259x - 333x) - \left( \frac{2}{3}x^2 + \frac{1}{3}x^2 \right) - 49,400
\]

\[
P(x) = 1926x - x^2 - 49,400
\]

### Summary of the equations:

- **Total Cost**: $ C(x) = 49,400 + \frac{1}{3}x^2 + 333x $
- **Total Revenue**: $ R(x) = 2259x - \frac{2}{3}x^2 $
- **Profit**: $ P(x) = 1926x - x^2 - 49,400 $

Let me know if you'd like to explore further or find specific values like the break-even point or the maximum profit. 

### Questions:
1. What is the break-even point for this company?
2. How many units should be produced to maximize profit?
3. What is the maximum profit the company can achieve?
4. At what production level does the company start incurring a loss?
5. How does an increase in fixed costs affect the profit function?

**Tip**: In these types of problems, analyzing the profit function for its maximum or minimum often involves taking the derivative and setting it to zero, which helps in identifying the optimal production level.

Suppose a company has fixed costs of $49,400 and variable cost per unit of 1/3x + 333 dollars, where x is the total number of units produced. Suppose further that the selling price of its product is 2259 - 2/3x dollars per unit.

Learn how to solve a business problem involving fixed costs, variable costs, and selling price using quadratic equations. This example shows how to calculate total cost, total revenue, and profit to determine optimal production levels for maximizing profit. Suitable for Grades 10-12.

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