Math Problem Statement

find the set of values for k for which the line y=x+k is tangent to y=x(power of 2)+x-2

Solution

To find the set of values for kk such that the line y=x+ky = x + k is tangent to the parabola y=x2+x2y = x^2 + x - 2, we need to follow these steps:

1. Set the equations equal to each other (since at the point of tangency, the yy-coordinates will be equal):

x+k=x2+x2x + k = x^2 + x - 2

2. Rearrange the equation to form a quadratic equation:

0=x2+x2(x+k)0 = x^2 + x - 2 - (x + k)

Simplifying:

0=x2+x2xk0 = x^2 + x - 2 - x - k

0=x22k0 = x^2 - 2 - k

x2=k+2x^2 = k + 2

Thus, the equation simplifies to:

[ x^2 = k + 2. This

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Tangency Conditions

Formulas

Quadratic equation formula: ax^2 + bx + c = 0
Condition for tangency: Discriminant (b^2 - 4ac) = 0

Theorems

Quadratic Formula
Tangency Condition for Parabolas

Suitable Grade Level

Grades 10-12