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The question asks to find the exact value of \(\sin(-\pi)\) using the unit circle. Let's walk through the solution.

1. **Step 1: Use the unit circle**  
   The angle \(-\pi\) corresponds to the angle rotated clockwise by \(\pi\) radians from the positive x-axis. This leads us to the point \((-1, 0)\) on the unit circle.

2. **Step 2: Recall the sine function**  
   The sine of an angle in the unit circle is the y-coordinate of the corresponding point. In this case, at \(-\pi\), the y-coordinate is \(0\).

Therefore:
\[
\sin(-\pi) = 0
\]

The correct answer is:
- Option A: \(\sin(-\pi) = 0\)

Would you like further details on this, or any additional explanations?

Here are five related questions:
1. What is \(\cos(-\pi)\)?
2. What is \(\tan(-\pi)\)?
3. How does the sine function behave for negative angles in general?
4. How is the unit circle used to define sine and cosine for angles greater than \(2\pi\)?
5. What is the sine of \(-\frac{\pi}{2}\)?

**Tip**: Remember that sine of any angle corresponds to the y-coordinate of the point on the unit circle, while cosine corresponds to the x-coordinate.

Use the unit circle, along with the definitions of the circular functions, to find the exact values for the given functions when s = -π.

This problem demonstrates how to use the unit circle to find the exact value of sin(-π). It reviews trigonometric concepts and explains how to identify the sine of an angle based on its coordinates on the unit circle. Suitable for high school students learning trigonometry.

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