The question asks to find the exact value of $\sin(-\pi)$ using the unit circle. Let's walk through the solution.

1. Step 1: Use the unit circle
   The angle $-\pi$ corresponds to the angle rotated clockwise by $\pi$ radians from the positive x-axis. This leads us to the point $(-1, 0)$ on the unit circle.

2. Step 2: Recall the sine function
   The sine of an angle in the unit circle is the y-coordinate of the corresponding point. In this case, at $-\pi$, the y-coordinate is $0$.

Therefore: $\sin(-\pi) = 0$

The correct answer is:

• Option A: $\sin(-\pi) = 0$

Would you like further details on this, or any additional explanations?

Here are five related questions:

1. What is $\cos(-\pi)$?
2. What is $\tan(-\pi)$?
3. How does the sine function behave for negative angles in general?
4. How is the unit circle used to define sine and cosine for angles greater than $2\pi$?
5. What is the sine of $-\frac{\pi}{2}$?

Tip: Remember that sine of any angle corresponds to the y-coordinate of the point on the unit circle, while cosine corresponds to the x-coordinate.