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The problem involves using the unit circle and trigonometric functions to evaluate values for \( s = -\pi \), and the question is asking for the value of \( \sin(-\pi) \).

### Step-by-step Solution:

1. **Understanding the Unit Circle**:
   - On the unit circle, the sine of an angle corresponds to the y-coordinate of the point where the terminal side of the angle intersects the circle.
   - The angle \( \pi \) radians is equivalent to 180°, which corresponds to the point \((-1, 0)\) on the unit circle.

2. **Sine Function**:
   - \( \sin(\theta) \) is the y-coordinate of the point on the unit circle.
   - Since \( \pi \) corresponds to the point \((-1, 0)\), the sine of \( \pi \) is 0.

3. **Negative Angles**:
   - For \( \sin(-\theta) \), we reflect the point across the x-axis. For \( \theta = \pi \), the reflection across the x-axis is still at \( ( -1, 0 ) \).
   - Therefore, \( \sin(-\pi) = 0 \).

### Conclusion:
The value of \( \sin(-\pi) \) is 0, so the correct answer is:
\[ A: \sin(-\pi) = 0 \]

Would you like further details, or do you have any questions about this? Here are five related questions to explore further:

1. What is the cosine value for \( \cos(-\pi) \)?
2. How do we compute \( \tan(-\pi) \) using the unit circle?
3. What is the general property of sine and cosine for negative angles?
4. Why does the unit circle have a radius of 1?
5. How can we find the sine of any angle greater than \( 2\pi \)?

**Tip**: Always visualize the angle on the unit circle to understand the behavior of trigonometric functions better.

Use the unit circle, along with the definitions of circular functions, to find the exact values for the given functions when s = -π. What is sin(-π)?

Learn how to solve trigonometric problems using the unit circle. This example shows how to find sin(-π) with a step-by-step solution. Suitable for high school students studying trigonometry.

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