Math Problem Statement

In the fig below, if gain is -12, find the value of R. Assume op-amp is ideal.

Solution

Given the circuit in the image, we need to find the value of RR given that the gain of the operational amplifier (op-amp) is -12.

Step-by-step Analysis

  1. Circuit Configuration:

    • The circuit is an inverting op-amp configuration with multiple resistors.
    • Resistors: 10kΩ10 \, k\Omega resistors are connected as feedback resistors along with the unknown resistor RR that branches at point B.
  2. Inverting Op-amp Gain Formula: For an inverting op-amp, the voltage gain (AvA_v) is given by: Av=RfRinA_v = -\frac{R_f}{R_{in}} Where:

    • RfR_f is the total feedback resistance.
    • RinR_{in} is the input resistor (here, 10kΩ10 \, k\Omega).
  3. Total Feedback Resistance:

    • In the circuit, the resistors form a combination in the feedback loop.
    • The resistors at the point B (two 10kΩ10 \, k\Omega resistors in series with RR in parallel): Rf=10kΩ+(10kΩ×R10kΩ+R)R_f = 10 \, k\Omega + \left( \frac{10 \, k\Omega \times R}{10 \, k\Omega + R} \right) Here, the two 10kΩ10 \, k\Omega resistors are in series, and their combination is in parallel with RR.
  4. Given Gain:

    • The gain is provided as -12.
    • Plugging into the gain formula: 12=Rf10kΩ-12 = -\frac{R_f}{10 \, k\Omega} Simplifying: Rf=12×10kΩ=120kΩR_f = 12 \times 10 \, k\Omega = 120 \, k\Omega
  5. Finding RR:

    • Substitute Rf=120kΩR_f = 120 \, k\Omega into the expression for total feedback resistance: 120kΩ=10kΩ+(10kΩ×R10kΩ+R)120 \, k\Omega = 10 \, k\Omega + \left( \frac{10 \, k\Omega \times R}{10 \, k\Omega + R} \right)
    • Subtract 10kΩ10 \, k\Omega from both sides: 110kΩ=10kΩ×R10kΩ+R110 \, k\Omega = \frac{10 \, k\Omega \times R}{10 \, k\Omega + R}
    • Cross-multiply to solve for RR: 110kΩ×(10kΩ+R)=10kΩ×R110 \, k\Omega \times (10 \, k\Omega + R) = 10 \, k\Omega \times R 1,100,000kΩ2+110kΩ×R=10kΩ×R1,100,000 \, k\Omega^2 + 110 \, k\Omega \times R = 10 \, k\Omega \times R
    • Isolate RR: 1,100,000kΩ2=10kΩ×R110kΩ×R1,100,000 \, k\Omega^2 = 10 \, k\Omega \times R - 110 \, k\Omega \times R 1,100,000kΩ2=100kΩ×R1,100,000 \, k\Omega^2 = -100 \, k\Omega \times R
    • Divide by 100kΩ-100 \, k\Omega to get RR: R=1,100,000kΩ2100kΩ=11kΩR = -\frac{1,100,000 \, k\Omega^2}{100 \, k\Omega} = 11 \, k\Omega

Final Answer

The value of RR is 11kΩ11 \, k\Omega.

Would you like further explanation or have any questions?

Related Questions

  1. How would the gain change if RR were doubled?
  2. What is the effect of changing the input resistor on the overall gain?
  3. How would you design a non-inverting amplifier with a gain of 12?
  4. What happens to the op-amp gain if one of the resistors in the feedback loop is open-circuited?
  5. How does the ideal op-amp assumption affect the accuracy of real-world circuit performance?

Tip: For accurate gain calculations in op-amp circuits, always check the configuration (inverting or non-inverting) and the arrangement of resistors in the feedback loop.

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Math Problem Analysis

Mathematical Concepts

Op-amp Circuits
Algebra
Resistor Combinations
Inverting Amplifier Gain

Formulas

Inverting amplifier gain: A_v = -R_f / R_in
Series and parallel resistor combinations: R_total = (R1 * R2) / (R1 + R2)

Theorems

Ohm's Law
Kirchhoff's Voltage Law

Suitable Grade Level

Undergraduate Electrical Engineering