Math Problem Statement

Given the measured values of voltage in the following circuit, calculate the value of resistor R4.

Solution

The circuit provided appears to be a combination of series and parallel resistances. We have the following key information from the circuit:

  • R1=10ΩR_1 = 10 \, \Omega
  • R2=20ΩR_2 = 20 \, \Omega
  • R3=20ΩR_3 = 20 \, \Omega
  • R4R_4 is unknown.
  • V3=20VV_3 = 20 \, V across R3R_3
  • The total voltage VT=120VV_T = 120 \, V

Steps to calculate R4R_4:

  1. Calculate the current through R3R_3: Using Ohm's law, the current through R3R_3 is given by: I3=V3R3=20V20Ω=1AI_3 = \frac{V_3}{R_3} = \frac{20 \, V}{20 \, \Omega} = 1 \, A Since R2R_2 and R3R_3 are in parallel, the current through R2R_2 will also be 1 A (because they have the same resistance).

  2. Total current through the parallel combination of R2R_2 and R3R_3: Iparallel=I2+I3=1A+1A=2AI_{\text{parallel}} = I_2 + I_3 = 1 \, A + 1 \, A = 2 \, A

  3. Voltage across the parallel combination: Since the total current through the parallel combination is 2 A and the equivalent resistance of the parallel branch is: Rparallel=R2R3R2+R3=20×2020+20=10ΩR_{\text{parallel}} = \frac{R_2 R_3}{R_2 + R_3} = \frac{20 \times 20}{20 + 20} = 10 \, \Omega The voltage across the parallel combination is: Vparallel=Iparallel×Rparallel=2A×10Ω=20VV_{\text{parallel}} = I_{\text{parallel}} \times R_{\text{parallel}} = 2 \, A \times 10 \, \Omega = 20 \, V

  4. Voltage across R1R_1: The total voltage VT=120VV_T = 120 \, V, and the voltage across the parallel branch is 20 V. Therefore, the voltage across R1R_1 is: V1=VTVparallel=120V20V=100VV_1 = V_T - V_{\text{parallel}} = 120 \, V - 20 \, V = 100 \, V

  5. Current through R1R_1: Using Ohm's law, the current through R1R_1 is: I1=V1R1=100V10Ω=10AI_1 = \frac{V_1}{R_1} = \frac{100 \, V}{10 \, \Omega} = 10 \, A

  6. Current through R4R_4: The current entering the junction before R2R_2, R3R_3, and R4R_4 is 10 A. The current through the parallel branch is 2 A, so the current through R4R_4 is: I4=I1Iparallel=10A2A=8AI_4 = I_1 - I_{\text{parallel}} = 10 \, A - 2 \, A = 8 \, A

  7. Calculate R4R_4: Using Ohm's law for R4R_4, where the voltage across R4R_4 is Vparallel=20VV_{\text{parallel}} = 20 \, V: R4=VparallelI4=20V8A=2.5ΩR_4 = \frac{V_{\text{parallel}}}{I_4} = \frac{20 \, V}{8 \, A} = 2.5 \, \Omega

Thus, the value of R4R_4 is 2.5 Ω.

Would you like further details or clarification?

Here are some related questions:

  1. How would the circuit change if R4R_4 were increased?
  2. How can we use Kirchhoff’s laws to solve this circuit?
  3. What happens to the total current if we reduce R2R_2 and R3R_3?
  4. What is the impact of adding another resistor in series with R1R_1?
  5. How would you approach this problem using Thevenin’s theorem?

Tip: When dealing with parallel resistors, always calculate the equivalent resistance first to simplify the analysis.

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Math Problem Analysis

Mathematical Concepts

Ohm's Law
Series and Parallel Circuits
Current Division
Voltage Division

Formulas

Ohm's Law: V = IR
Parallel Resistance: 1/R_parallel = 1/R1 + 1/R2
Series Resistance: R_total = R1 + R2

Theorems

Ohm's Law
Series-Parallel Circuit Analysis

Suitable Grade Level

High School (Grades 9-12)