Math Problem Statement
Solution
The circuit provided appears to be a combination of series and parallel resistances. We have the following key information from the circuit:
- is unknown.
- across
- The total voltage
Steps to calculate :
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Calculate the current through : Using Ohm's law, the current through is given by: Since and are in parallel, the current through will also be 1 A (because they have the same resistance).
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Total current through the parallel combination of and :
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Voltage across the parallel combination: Since the total current through the parallel combination is 2 A and the equivalent resistance of the parallel branch is: The voltage across the parallel combination is:
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Voltage across : The total voltage , and the voltage across the parallel branch is 20 V. Therefore, the voltage across is:
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Current through : Using Ohm's law, the current through is:
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Current through : The current entering the junction before , , and is 10 A. The current through the parallel branch is 2 A, so the current through is:
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Calculate : Using Ohm's law for , where the voltage across is :
Thus, the value of is 2.5 Ω.
Would you like further details or clarification?
Here are some related questions:
- How would the circuit change if were increased?
- How can we use Kirchhoff’s laws to solve this circuit?
- What happens to the total current if we reduce and ?
- What is the impact of adding another resistor in series with ?
- How would you approach this problem using Thevenin’s theorem?
Tip: When dealing with parallel resistors, always calculate the equivalent resistance first to simplify the analysis.
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Math Problem Analysis
Mathematical Concepts
Ohm's Law
Series and Parallel Circuits
Current Division
Voltage Division
Formulas
Ohm's Law: V = IR
Parallel Resistance: 1/R_parallel = 1/R1 + 1/R2
Series Resistance: R_total = R1 + R2
Theorems
Ohm's Law
Series-Parallel Circuit Analysis
Suitable Grade Level
High School (Grades 9-12)
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