To find the range of the function $f(x) = 2x + 3$ for the given domain $\{-2, -1, 0, 1, 2\}$, we will substitute each value from the domain into the function and compute the corresponding $f(x)$.

1. For $x = -2$: $f(-2) = 2(-2) + 3 = -4 + 3 = -1$

2. For $x = -1$: $f(-1) = 2(-1) + 3 = -2 + 3 = 1$

3. For $x = 0$: $f(0) = 2(0) + 3 = 0 + 3 = 3$

4. For $x = 1$: $f(1) = 2(1) + 3 = 2 + 3 = 5$

5. For $x = 2$: $f(2) = 2(2) + 3 = 4 + 3 = 7$

Thus, the corresponding range for the given domain is $\{-1, 1, 3, 5, 7\}$.

Would you like further details or have any questions?

Here are 5 related questions:

1. What is the general process for finding the range of any linear function?
2. How would the range change if the function had a different slope?
3. What would the range be if the domain were extended to more values?
4. How can the range of quadratic functions be determined?
5. How does the concept of range differ for non-linear functions?

Tip: When dealing with linear functions, the range is typically found by plugging in values from the domain directly into the function to get corresponding outputs.