To find the range of the function $f(x) = -5x + 3$ for the given domain $\{-2, -1, 0, 1, 2\}$, we will evaluate the function at each value of $x$.

1. For $x = -2$: $f(-2) = -5(-2) + 3 = 10 + 3 = 13$

2. For $x = -1$: $f(-1) = -5(-1) + 3 = 5 + 3 = 8$

3. For $x = 0$: $f(0) = -5(0) + 3 = 0 + 3 = 3$

4. For $x = 1$: $f(1) = -5(1) + 3 = -5 + 3 = -2$

5. For $x = 2$: $f(2) = -5(2) + 3 = -10 + 3 = -7$

Thus, the range of the function for the given domain $\{-2, -1, 0, 1, 2\}$ is:

$\{13, 8, 3, -2, -7\}$

Would you like further details or have any questions?

Here are 5 related questions to explore:

1. What is the slope of the function $f(x) = -5x + 3$?
2. How does changing the domain affect the range of a function?
3. How would the range change if the function was $f(x) = 5x + 3$ instead?
4. What is the meaning of the y-intercept in the function $f(x) = -5x + 3$?
5. How can you graph the function based on the calculated points?

Tip: In linear functions, the slope determines how fast the function increases or decreases as $x$ changes.