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The function \( g(x) = 1 - 2x \) is given with the domain \( \{-1, 0, 1, 2\} \). Let's compute the range of the function by plugging in each value of \( x \) from the domain and calculating the corresponding \( g(x) \).

1. For \( x = -1 \):
   \[
   g(-1) = 1 - 2(-1) = 1 + 2 = 3
   \]

2. For \( x = 0 \):
   \[
   g(0) = 1 - 2(0) = 1
   \]

3. For \( x = 1 \):
   \[
   g(1) = 1 - 2(1) = 1 - 2 = -1
   \]

4. For \( x = 2 \):
   \[
   g(2) = 1 - 2(2) = 1 - 4 = -3
   \]

Now, we have the range values \( g(-1) = 3 \), \( g(0) = 1 \), \( g(1) = -1 \), and \( g(2) = -3 \).

Thus, the range of the function is \( \{3, 1, -1, -3\} \).

Next, you need to graph the points \( (-1, 3) \), \( (0, 1) \), \( (1, -1) \), and \( (2, -3) \) on the provided graph.

Do you have any questions or would you like further details on this?

Here are five related questions:
1. What is the slope of the function \( g(x) = 1 - 2x \)?
2. How would the range change if the domain was extended to include more values?
3. Can you express \( g(x) \) in terms of its intercepts?
4. How do you determine the domain of a linear function?
5. How does the range of a function relate to its domain?

**Tip:** When finding the range of a function, always substitute the domain values into the function and solve step by step!

The function g(x) = 1 - 2x is given with the domain {-1, 0, 1, 2}. Write the range of g using set notation. Then graph g.

Learn how to find the range of the function g(x) = 1 - 2x for the domain {-1, 0, 1, 2}. This problem involves substituting domain values into a linear function and plotting the resulting points on a graph. Suitable for students in Grades 8-9.

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