Math Problem Statement

Find the missing interior and exterior angles of the given polygons.

Solution

Let's analyze and solve the missing angles in the provided polygons. Here's the breakdown for each problem:

Problem 1:

  • The given angles are 8484^\circ, 100100^\circ, and 121121^\circ.

  • The sum of the interior angles of a quadrilateral is 360360^\circ.

    x=360(84+100+121)=360305=55x = 360^\circ - (84^\circ + 100^\circ + 121^\circ) = 360^\circ - 305^\circ = 55^\circ

    So, x=55x = 55^\circ.

Problem 2:

  • The given angles are 100100^\circ and 120120^\circ.

  • For a triangle, the sum of the interior angles is 180180^\circ.

    x=180(100+120)=180220=40x = 180^\circ - (100^\circ + 120^\circ) = 180^\circ - 220^\circ = -40^\circ

    But this cannot be correct since a triangle cannot have a negative angle, so the problem might have an error. Please verify the image again for this one.

Problem 3:

  • The given angles are 9595^\circ and 7070^\circ.

  • The sum of the interior angles of a triangle is 180180^\circ.

    x=180(95+70)=180165=15x = 180^\circ - (95^\circ + 70^\circ) = 180^\circ - 165^\circ = 15^\circ

    So, x=15x = 15^\circ.

Problem 4:

  • The given angles are 120120^\circ, 8585^\circ, and 7070^\circ.

  • This is a quadrilateral, and the sum of interior angles is 360360^\circ.

    x=360(120+85+70)=360275=85x = 360^\circ - (120^\circ + 85^\circ + 70^\circ) = 360^\circ - 275^\circ = 85^\circ

    So, x=85x = 85^\circ.

Problem 5:

  • The given angles are 5555^\circ, 102102^\circ, and 8080^\circ.

  • This is a quadrilateral.

    x=360(55+102+80)=360237=123x = 360^\circ - (55^\circ + 102^\circ + 80^\circ) = 360^\circ - 237^\circ = 123^\circ

    So, x=123x = 123^\circ.

Problem 6:

  • The given angles are 9191^\circ and 8080^\circ.

  • The sum of the interior angles of a triangle is 180180^\circ.

    x=180(91+80)=180171=9x = 180^\circ - (91^\circ + 80^\circ) = 180^\circ - 171^\circ = 9^\circ

    So, x=9x = 9^\circ.

Problem 7:

  • The given angles are 7575^\circ, 4545^\circ, and 6363^\circ.

  • The sum of the interior angles of a quadrilateral is 360360^\circ.

    x=360(75+45+63)=360183=177x = 360^\circ - (75^\circ + 45^\circ + 63^\circ) = 360^\circ - 183^\circ = 177^\circ

    So, x=177x = 177^\circ.

Problem 8:

  • The given angles are 8080^\circ and 6363^\circ.

  • This is a triangle.

    x=180(80+63)=180143=37x = 180^\circ - (80^\circ + 63^\circ) = 180^\circ - 143^\circ = 37^\circ

    So, x=37x = 37^\circ.


Would you like further details on any of the steps?

5 Related Questions:

  1. How do you calculate the sum of interior angles for any polygon?
  2. What are the exterior angles of a polygon, and how are they related to the interior angles?
  3. How do you handle problems with missing angles in polygons?
  4. Can the sum of exterior angles of any polygon change with the number of sides?
  5. What is the role of supplementary angles in finding missing angles in polygons?

Tip:

Always check if the sum of angles provided makes sense for the polygon in question (e.g., the sum of the interior angles of a triangle must be 180°).

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Math Problem Analysis

Mathematical Concepts

Geometry
Polygons
Interior Angles
Exterior Angles

Formulas

Sum of interior angles of a polygon = (n - 2) * 180°
Sum of exterior angles of a polygon = 360°
For a triangle, sum of interior angles = 180°
For a quadrilateral, sum of interior angles = 360°

Theorems

Interior Angle Sum Theorem
Exterior Angle Sum Theorem

Suitable Grade Level

Grades 6-8