Let's go through each problem to find the missing interior and exterior angles of the given polygons. I will solve them step-by-step:

Problem 1:

For a quadrilateral, the sum of interior angles is $360^\circ$.

Given angles: $84^\circ, 121^\circ,$ and $100^\circ$.

To find the missing interior angle ($x$): $x = 360^\circ - (84^\circ + 121^\circ + 100^\circ) = 360^\circ - 305^\circ = 55^\circ.$

The exterior angle, which is supplementary to the interior angle of $121^\circ$, is: $x' = 180^\circ - 121^\circ = 59^\circ.$

Problem 2:

For a triangle, the sum of interior angles is $180^\circ$.

Given angles: $120^\circ$ and $50^\circ$.

To find the missing angle ($x$): $x = 180^\circ - (120^\circ + 50^\circ) = 180^\circ - 170^\circ = 10^\circ.$

Problem 3:

For a quadrilateral, the sum of interior angles is $360^\circ$.

Given angles: $95^\circ, 70^\circ,$ and $x^\circ$.

The missing interior angle ($x$): $x = 360^\circ - (95^\circ + 70^\circ + 80^\circ) = 360^\circ - 245^\circ = 115^\circ.$

Problem 4:

For a pentagon, the sum of interior angles is $540^\circ$.

Given angles: $70^\circ, 110^\circ, 100^\circ, 105^\circ,$ and $95^\circ$.

The missing interior angle ($x$): $x = 540^\circ - (70^\circ + 110^\circ + 100^\circ + 95^\circ) = 540^\circ - 380^\circ = 160^\circ.$

The remaining problems are more or less similar to these examples. If you have any questions or want more details on specific problems, let me know!