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The problem requires finding the midpoint, \( M \), of the line segment \( \overline{AB} \), where the coordinates of points \( A \) and \( B \) are given as \( A(2, 5) \) and \( B(-6, -3) \).

The formula to find the midpoint between two points \( A(x_1, y_1) \) and \( B(x_2, y_2) \) is:

\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

Substituting the given coordinates \( A(2, 5) \) and \( B(-6, -3) \) into the formula:

\[
M_x = \frac{2 + (-6)}{2} = \frac{-4}{2} = -2
\]
\[
M_y = \frac{5 + (-3)}{2} = \frac{2}{2} = 1
\]

Thus, the midpoint \( M \) is:

\[
M = (-2, 1)
\]

Would you like any additional details or have further questions? 

Here are five related questions to deepen your understanding:
1. How would the midpoint formula change in 3D space?
2. What is the distance between points \( A \) and \( B \)?
3. How do you interpret the midpoint geometrically?
4. Can you find the slope of the line segment \( \overline{AB} \)?
5. What happens to the midpoint if both points \( A \) and \( B \) move along the same line?

**Tip:** When calculating midpoints, always ensure you handle both positive and negative signs carefully to avoid errors.

Find the midpoint, M, of line segment AB where A = (2, 5) and B = (-6, -3).

This problem demonstrates how to find the midpoint M of a line segment AB, given the coordinates A(2, 5) and B(-6, -3). It uses the midpoint formula and is suitable for students in Grades 6-8.

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