https://file.aiquickdraw.com/mathbot/file/1728411842093lcpb9ezi.jpg

From the diagram, we are dealing with angle relationships in a geometric figure. Specifically, we know that:

- \( \angle BAC = 25^\circ \).
- There is a pair of congruent marks (the small tick) between segments \( AB \) and \( AC \), which indicates that \( \triangle ABC \) is isosceles, meaning that \( \angle ABC = \angle BAC = 25^\circ \).
- The goal is to find \( \angle CAD \).

The angle \( \angle BAD \) is a straight angle, which means it measures \( 180^\circ \). Therefore, the sum of the angles \( \angle BAC \), \( \angle CAD \), and \( \angle DAB \) must be equal to \( 180^\circ \).

Now, \( \angle BAC = 25^\circ \). The remaining angle \( \angle CAD \) is the supplementary angle to \( \angle BAC \), because \( \angle BAD \) is a straight line. Hence,

\[
\angle CAD = 180^\circ - 25^\circ = 155^\circ.
\]

Thus, \( \angle CAD = 155^\circ \).

Would you like any further explanation or details on this solution?

Here are some related questions:
1. What is the sum of angles in any triangle?
2. How do you identify isosceles triangles from diagrams?
3. What is the relationship between a straight line and angles on that line?
4. What is an exterior angle in geometry?
5. How does congruence affect the relationship between angles in triangles?

**Tip:** In problems involving straight lines, angles on one side of the line always sum to \(180^\circ\), helping to solve for unknown angles easily.

In this geometry problem, we solve for m∠CAD when m∠BAC = 25°. Using the properties of supplementary angles and angle sum relationships, we find m∠CAD. Suitable for students in Grades 6-8.

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