Math Problem Statement

solve

In triangle ABC, ∠C is a right angle and CD is the altitude to AB. Find the angles in triangles CBD and CAD if m∠A = 65°.

Solution

To solve this problem, we first need to break down the given information and understand the geometry of the triangle.

Step-by-step analysis:

  • In triangle ABC\triangle ABC, we know that:
    • C\angle C is a right angle (9090^\circ).
    • CDCD is the altitude to side ABAB, which means CDCD is perpendicular to ABAB and divides ABC\triangle ABC into two smaller right triangles CBD\triangle CBD and CAD\triangle CAD.
    • A=65\angle A = 65^\circ, as given.

From this, let's start calculating the unknown angles in triangles CBD\triangle CBD and CAD\triangle CAD.

Triangle ABC\triangle ABC:

Since ABC\triangle ABC is a right triangle, we can calculate B\angle B: A+B+C=180\angle A + \angle B + \angle C = 180^\circ Substituting A=65\angle A = 65^\circ and C=90\angle C = 90^\circ: 65+B+90=18065^\circ + \angle B + 90^\circ = 180^\circ B=180155=25\angle B = 180^\circ - 155^\circ = 25^\circ So, B=25\angle B = 25^\circ.

Triangle CBD\triangle CBD (Right triangle):

  • DCB=90\angle DCB = 90^\circ because CDCD is perpendicular to ABAB.
  • B\angle B in ABC\triangle ABC is shared with CBD\triangle CBD, so DBC=25\angle DBC = 25^\circ.

Now, we can calculate CDB\angle CDB: DBC+DCB+CDB=180\angle DBC + \angle DCB + \angle CDB = 180^\circ 25+90+CDB=18025^\circ + 90^\circ + \angle CDB = 180^\circ CDB=180115=65\angle CDB = 180^\circ - 115^\circ = 65^\circ

Triangle CAD\triangle CAD (Right triangle):

  • ACD=90\angle ACD = 90^\circ because CDCD is perpendicular to ABAB.
  • A\angle A in ABC\triangle ABC is shared with CAD\triangle CAD, so DAC=65\angle DAC = 65^\circ.

Now, we can calculate ADC\angle ADC: DAC+ACD+ADC=180\angle DAC + \angle ACD + \angle ADC = 180^\circ 65+90+ADC=18065^\circ + 90^\circ + \angle ADC = 180^\circ ADC=180155=25\angle ADC = 180^\circ - 155^\circ = 25^\circ

Final Angles:

  • mDBC=25m \angle DBC = 25^\circ
  • mDCB=90m \angle DCB = 90^\circ
  • mCDB=65m \angle CDB = 65^\circ
  • mACD=90m \angle ACD = 90^\circ
  • mADC=25m \angle ADC = 25^\circ

Would you like a further breakdown of any step or details on specific parts? Here are some related questions to deepen understanding:

  1. Why is CDCD perpendicular to ABAB?
  2. How do the angles in a right triangle add up to 180180^\circ?
  3. What is the significance of C=90\angle C = 90^\circ in the context of the altitude?
  4. How are the angles in ABC\triangle ABC related to the smaller triangles CBD\triangle CBD and CAD\triangle CAD?
  5. Can we use trigonometric ratios to find the lengths of the sides in these triangles?

Tip: Always check if a triangle is a right triangle when one angle is 9090^\circ, as this simplifies calculations using the sum of angles.

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Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles
Altitude
Sum of Angles in a Triangle

Formulas

Sum of angles in a triangle = 180°
Right triangle property: one angle is 90°

Theorems

Angle sum property of triangles
Right triangle properties

Suitable Grade Level

Grades 9-12