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The problem asks for the length of segment \( CD \), given that \( DE = 6 \) and \( CE = 15 \).

To find \( CD \), you can use the fact that \( CE = CD + DE \). We can express this as:

\[
CE = CD + DE
\]

Substituting the given values:

\[
15 = CD + 6
\]

Now, solve for \( CD \):

\[
CD = 15 - 6 = 9
\]

Thus, the length of segment \( CD \) is \( 9 \).

Would you like more details or have any questions? Here are five related questions to further explore:

1. If \( DE \) was 7 instead of 6, what would \( CD \) be?
2. How would the calculation change if \( CE \) was 20 and \( DE \) remained 6?
3. Can you find the value of \( CE \) if \( CD = 10 \) and \( DE = 5 \)?
4. What is the relationship between the lengths of segments \( CD \) and \( DE \)?
5. How would you express \( CD \) in terms of \( CE \) and \( DE \)?

**Tip:** When solving problems involving segments, always verify that the sum of smaller segments equals the total segment length to ensure your calculations are correct.

Learn how to calculate the length of segment CD when DE is 6 and CE is 15. This problem uses basic algebra and the Segment Addition Postulate, suitable for students in Grades 5-7.

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