Math Problem Statement

D is the midpoint of CE. If DE = 2x + 9 and CE = 10x + 9, what is DE?

Solution

To solve for DEDE, given that DD is the midpoint of CE\overline{CE}, we can set up the following relationships:

Since DD is the midpoint of CE\overline{CE}, the segment DEDE should be half the length of CECE. Mathematically, we can express this as: DE=12CEDE = \frac{1}{2} \cdot CE

We are given:

  • DE=2x+9DE = 2x + 9
  • CE=10x+9CE = 10x + 9

Substitute CE=10x+9CE = 10x + 9 into the equation for DEDE being half of CECE: DE=12(10x+9)DE = \frac{1}{2} \cdot (10x + 9)

Now, set this expression equal to the given expression for DEDE: 2x+9=12(10x+9)2x + 9 = \frac{1}{2} \cdot (10x + 9)

To eliminate the fraction, multiply both sides by 2: 2(2x+9)=10x+92(2x + 9) = 10x + 9 4x+18=10x+94x + 18 = 10x + 9

Now, solve for xx:

  1. Subtract 4x4x from both sides: 18=6x+918 = 6x + 9
  2. Subtract 9 from both sides: 9=6x9 = 6x
  3. Divide by 6: x=32x = \frac{3}{2}

With x=32x = \frac{3}{2}, substitute back to find DEDE: DE=2x+9=2(32)+9=3+9=12DE = 2x + 9 = 2\left(\frac{3}{2}\right) + 9 = 3 + 9 = 12

So, the length of DEDE is: 12\boxed{12}

Would you like further explanation, or do you have any questions?

Related Questions:

  1. How would the solution change if DD were not the midpoint?
  2. What if CECE had a different expression?
  3. Can you find CDCD based on the information given?
  4. How would we approach this if we only knew CDCD?
  5. Could this method be used for other geometric figures?

Tip:

Always check if simplifying the equation at the beginning helps clarify the solution process.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Midpoint

Formulas

Midpoint formula
Equation solving

Theorems

Midpoint theorem

Suitable Grade Level

Grades 8-10