Math Problem Statement

What is the length of BD? Round to one decimal place.

Solution

To find the length of BDBD in the given triangle ABCABC, with BC=5.7BC = 5.7, AC=5.1AC = 5.1, and CD=3.2CD = 3.2, we can apply the cosine rule, assuming BCD\angle BCD and BDC\angle BDC are known or can be calculated using the triangle sides.

Step 1: Apply the Cosine Rule in Triangle BCD

We first calculate BCD\angle BCD using the cosine rule in triangle ACDACD:

cos(ACD)=AC2+CD2AD22×AC×CD\cos(\angle ACD) = \frac{AC^2 + CD^2 - AD^2}{2 \times AC \times CD}

Given AC=5.1AC = 5.1, CD=3.2CD = 3.2, and AD=BDAD = BD, we then use the cosine rule to find BDBD:

BD2=BC2+CD22×BC×CD×cos(BCD)BD^2 = BC^2 + CD^2 - 2 \times BC \times CD \times \cos(\angle BCD)

Step 2: Calculate BDBD

Given BC=5.7BC = 5.7 and CD=3.2CD = 3.2, the above formula will yield BDBD. Let's compute this step-by-step.

Let's first calculate BCD\angle BCD and then find BDBD.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Cosine Rule

Formulas

Cosine Rule: c^2 = a^2 + b^2 - 2ab * cos(C)
Trigonometric calculations for angles and sides

Theorems

Cosine Rule

Suitable Grade Level

Grades 9-11