Math Problem Statement

The diagram shows triangle ABC with D on AC and E on AB. DE is a straight line. AD = 27 m, AE = 39 m, DE = 23 m, and BC = 65 m. Angle ABC = 68°. Calculate the length of CD.

Solution

We are given a triangle ABCABC with points DD on side ACAC and EE on side ABAB, and a straight line DEDE. Our task is to find the length of side CDCD.

Information given:

  • AD=27mAD = 27 \, \text{m}
  • AE=39mAE = 39 \, \text{m}
  • DE=23mDE = 23 \, \text{m}
  • BC=65mBC = 65 \, \text{m}
  • ABC=68\angle ABC = 68^\circ

The solution involves using the sine rule in triangles and potentially the cosine rule.

Approach:

  1. First, we observe two triangles: ABC\triangle ABC and ADE\triangle ADE. The information given focuses more on ABC\triangle ABC.

  2. Use the sine rule to relate the sides and angles in ABC\triangle ABC. We know: ABsin(ACB)=BCsin(BAC)=ACsin(ABC)\frac{AB}{\sin(\angle ACB)} = \frac{BC}{\sin(\angle BAC)} = \frac{AC}{\sin(\angle ABC)}

    We are missing some key angles but we know that ABC=68\angle ABC = 68^\circ. To use the sine rule, we might need to calculate or estimate some angles or side lengths.

  3. We may also use the cosine rule in ABC\triangle ABC since we have two sides and the included angle: AC2=AB2+BC22×AB×BC×cos(ABC)AC^2 = AB^2 + BC^2 - 2 \times AB \times BC \times \cos(\angle ABC)

Let's work this out:

  • AB=AD+DE+AE=27+23+39=89mAB = AD + DE + AE = 27 + 23 + 39 = 89 \, \text{m}
  • Now apply the cosine rule to find ACAC: AC2=892+6522×89×65×cos(68)AC^2 = 89^2 + 65^2 - 2 \times 89 \times 65 \times \cos(68^\circ) AC2=7921+42252×89×65×0.3746AC^2 = 7921 + 4225 - 2 \times 89 \times 65 \times 0.3746 AC2=121464335.67=7810.33AC^2 = 12146 - 4335.67 = 7810.33 AC=7810.3388.38mAC = \sqrt{7810.33} \approx 88.38 \, \text{m}
  1. Now that we have ACAC, we can find CDCD by subtracting ADAD from ACAC: CD=ACAD=88.3827=61.38mCD = AC - AD = 88.38 - 27 = 61.38 \, \text{m}

Thus, the length of CDCD is approximately 61.38m61.38 \, \text{m}.

Would you like more details or have any questions?

Here are 5 related questions:

  1. How do we apply the sine rule in non-right-angled triangles?
  2. What is the significance of the cosine rule in triangle geometry?
  3. Can you explain how angle-side relationships affect triangle calculations?
  4. What would be a step-by-step guide for using the cosine rule?
  5. How can we apply trigonometry to solve problems involving multiple triangles?

Tip: When solving for side lengths in non-right-angled triangles, always check if the sine or cosine rule applies based on the available data.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Geometry

Formulas

Sine rule: (AB/sin(∠ACB)) = (BC/sin(∠BAC)) = (AC/sin(∠ABC))
Cosine rule: AC^2 = AB^2 + BC^2 - 2 * AB * BC * cos(∠ABC)

Theorems

Sine rule
Cosine rule

Suitable Grade Level

Grades 9-11