Given the function \( h(x) = 4x^2 + 3x - 5 \), we are asked to find \( h(t) \), which means we simply substitute \( x \) with \( t \) in the given equation.

Thus, the function becomes:

\[
h(t) = 4t^2 + 3t - 5
\]

This is the expression for \( h(t) \).

Would you like further details or have any other questions?

Here are 5 related questions to practice:
1. What is \( h(2) \) for the function \( h(x) = 4x^2 + 3x - 5 \)?
2. How do you find \( h(-1) \) for the same function?
3. Can you determine the roots of \( h(x) = 0 \)?
4. What is the derivative of \( h(x) \)?
5. What is the value of \( h(0) \)?

**Tip**: When substituting values into a function, ensure you replace all instances of the variable!

Discover how to substitute t for x in the quadratic function h(x) = 4x^2 + 3x - 5. This solution explains key concepts like substitution in functions, quadratic equations, and algebraic operations. Ideal for students in Grades 7-9.

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