To find \( h(t) \), you simply substitute \( t \) for \( x \) in the function \( h(x) = 4x^2 + 3x - 5 \).

Thus:

\[
h(t) = 4t^2 + 3t - 5
\]

This is the expression for \( h(t) \).

Would you like more details, or do you have any questions?

Here are 5 related questions:
1. What is the value of \( h(2) \) for the same function?
2. How do you find the derivative of \( h(x) \)?
3. What would be the graph of \( h(x) = 4x^2 + 3x - 5 \)?
4. How do you find the roots of \( h(x) = 0 \)?
5. What is the maximum or minimum point of \( h(x) \)?

**Tip:** Always carefully substitute variables into functions to avoid mistakes, especially in more complex expressions!

Find h(t) for the function h(x) = 4x^2 + 3x - 5.

Learn how to substitute variables into functions by finding h(t) for the function h(x) = 4x^2 + 3x - 5. This example covers basic algebraic substitution, suitable for students in Grades 9-11.

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