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The problem you've provided is:

\[
f(x) = -x^2, \text{ find } x \text{ when } f(-5)
\]

To solve this, we simply need to substitute \( x = -5 \) into the given function \( f(x) = -x^2 \).

### Step-by-Step Solution:

1. The function is \( f(x) = -x^2 \).
2. Substituting \( x = -5 \) into the function:

\[
f(-5) = -(-5)^2 = -(25) = -25
\]

Thus, \( f(-5) = -25 \).

Would you like more details or explanations on any specific part? 

Here are 5 related questions you might find useful:
1. What is the general form of a quadratic function?
2. How do you find the vertex of a quadratic function like \( f(x) = -x^2 \)?
3. What are the effects of negative coefficients on parabolas?
4. Can you explain how to graph quadratic functions?
5. What are the roots or solutions of \( f(x) = -x^2 \)?

**Tip:** When evaluating a function, always follow the order of operations (PEMDAS), particularly when dealing with negative signs and exponents.

Learn how to find the value of f(-5) for the quadratic function f(x) = -x^2. This problem involves substituting -5 into the function and simplifying to get the answer. Suitable for students in Grades 9-10.

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