To solve $f(-10)$ for $f(x) = -x^2$, follow these steps:

Step 1: Substitute $-10$ into the function

$f(-10) = -(-10)^2$

Step 2: Square the input

$(-10)^2 = 100$

Step 3: Apply the negative sign

$f(-10) = -100$

Final Answer:

$f(-10) = -100$

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Would you like additional explanations or related examples?

Five Related Questions:

1. What is $f(0)$ for $f(x) = -x^2$?
2. How do you determine the vertex of the function $f(x) = -x^2$?
3. What is the domain and range of $f(x) = -x^2$?
4. How would $f(x) = -x^2$ change if it were $f(x) = x^2$?
5. What are the x-intercepts of $f(x) = -x^2$?

Tip:

For quadratic functions, the sign of the leading coefficient determines whether the parabola opens upwards (positive) or downwards (negative).