When x=-3 what how do you evaluate the function f(x)=-x^2+5

To evaluate the function \( f(x) = -x^2 + 5 \) when \( x = -3 \), follow these steps:

1. Substitute \( x = -3 \) into the function:
   \[
   f(-3) = -(-3)^2 + 5
   \]

2. First, calculate \( (-3)^2 \), which is \( 9 \):
   \[
   f(-3) = -9 + 5
   \]

3. Now, add \( -9 \) and \( 5 \):
   \[
   f(-3) = -4
   \]

So, when \( x = -3 \), the value of the function is \( f(-3) = -4 \).

Would you like a more detailed explanation or have any questions?

Here are 5 related questions:
1. What is the vertex of the function \( f(x) = -x^2 + 5 \)?
2. How do you determine the domain and range of \( f(x) = -x^2 + 5 \)?
3. What happens to \( f(x) = -x^2 + 5 \) when \( x = 0 \)?
4. Can you explain how the graph of \( f(x) = -x^2 + 5 \) looks?
5. How do you solve \( f(x) = 0 \) for \( f(x) = -x^2 + 5 \)?

**Tip:** In quadratic functions like \( f(x) = -x^2 + 5 \), the negative sign in front of \( x^2 \) flips the parabola downward.

When x=-3, how do you evaluate the function f(x) = -x^2 + 5?

Learn how to evaluate the quadratic function f(x) = -x^2 + 5 when x = -3. This detailed guide walks through substituting x, simplifying the expression, and solving for the final result. Suitable for students in Grades 7-9.

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