Math Problem Statement

Given f, of, x, equals, minus, x, squaredf(x)=−x 2 , find f, of, minus, 1f(−1)

Solution

Given the function f(x)=x2f(x) = -x^2, we want to find f(1)f(-1).

Substitute 1-1 for xx in the function:

f(1)=(1)2f(-1) = -(-1)^2

Calculate (1)2(-1)^2:

(1)2=1(-1)^2 = 1

So, the expression becomes:

f(1)=1f(-1) = -1

Thus, f(1)=1f(-1) = -1.

Would you like more details or have any questions?

Here are 5 related questions:

  1. What is f(2)f(2) for the function f(x)=x2f(x) = -x^2?
  2. How does the graph of f(x)=x2f(x) = -x^2 differ from f(x)=x2f(x) = x^2?
  3. What is the vertex of the parabola represented by f(x)=x2f(x) = -x^2?
  4. How would you find the roots of the function f(x)=x2f(x) = -x^2?
  5. What is the range of the function f(x)=x2f(x) = -x^2?

Tip: When substituting values into a function, always follow the order of operations, especially with negative numbers and exponents.

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions
Quadratic Functions

Formulas

f(x) = -x^2

Theorems

Basic Function Substitution

Suitable Grade Level

Grades 7-9