The problem remains clear:

We need to evaluate $f(6)$ and $f(0)$ for the given function:

$f(x) = x^2 - 7x - 10$

Solution Recap:

1. For $f(6)$: Substitute $x = 6$: $f(6) = 6^2 - 7(6) - 10$ $f(6) = 36 - 42 - 10 = -16$ So, $f(6) = -16$.

2. For $f(0)$: Substitute $x = 0$: $f(0) = 0^2 - 7(0) - 10$ $f(0) = -10$ So, $f(0) = -10$.

Final Answers:

• a) $f(6) = -16$
• b) $f(0) = -10$

Let me know if you'd like further clarification or expansion on this! Would you also like to explore related problems like graphing the function or finding its roots?