Math Problem Statement

If EF bisects CD, CG = 5x - 1, GD = 7x - 13, EF = 6x - 4, and GF = 13, find EG.

Solution

The problem from the image states:

"14. If EF bisects CDCD, CG=5x1CG = 5x - 1, GD=7x13GD = 7x - 13, EF=6x4EF = 6x - 4, and GF=13GF = 13, find EGEG."

Solution:

Since EFEF bisects CDCD at point GG, we know that:

CG=GDCG = GD

Given:

  • CG=5x1CG = 5x - 1
  • GD=7x13GD = 7x - 13

Since CG=GDCG = GD:

5x1=7x135x - 1 = 7x - 13

Now, solve for xx:

  1. Subtract 5x5x from both sides:

1=2x13-1 = 2x - 13

  1. Add 13 to both sides:

12=2x12 = 2x

  1. Divide by 2:

x=6x = 6

Now that we have x=6x = 6, substitute this value back into the expressions for CGCG and GDGD:

  • CG=5(6)1=301=29CG = 5(6) - 1 = 30 - 1 = 29
  • GD=7(6)13=4213=29GD = 7(6) - 13 = 42 - 13 = 29

Thus, CG=GD=29CG = GD = 29, confirming the bisection.

Find EGEG:

Given that EF=6x4EF = 6x - 4 and GF=13GF = 13, substitute x=6x = 6 into the expression for EFEF:

EF=6(6)4=364=32EF = 6(6) - 4 = 36 - 4 = 32

Since EG=EFGFEG = EF - GF, we have:

EG=3213=19EG = 32 - 13 = 19

Final Answer:

EG=19EG = 19

Would you like more details or have any questions?

Here are some related questions to further your understanding:

  1. How would the solution change if EFEF didn’t bisect CDCD?
  2. Can you find the length of CFCF using the information from the problem?
  3. What happens to EGEG if the value of xx increases or decreases?
  4. How is the concept of line bisection important in solving geometry problems?
  5. If the coordinates of these points were given, could you use a coordinate geometry approach to solve the problem?

Tip: In geometry, identifying equal segments or angles can simplify complex problems by reducing them to solvable algebraic equations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Line Segments
Bisection

Formulas

CG = GD
EG = EF - GF

Theorems

Line Bisection Theorem

Suitable Grade Level

Grades 8-10