Math Problem Statement

If EF bisects CD, CG = 11x + 5, GD = 13x - 15, and EF = 8x + 2, find x and EF.

Solution

The problem asks to find the values of xx and EFEF, given that line EFEF bisects line CDCD, and the following algebraic expressions:

  • CG=11x+5CG = 11x + 5
  • GD=13x15GD = 13x - 15
  • EF=8x+2EF = 8x + 2

Geometry Setup:

Since EFEF bisects CDCD at point GG, this implies that CG=GDCG = GD. Thus, we can set up the equation: CG=GDCG = GD 11x+5=13x1511x + 5 = 13x - 15

Algebra Setup:

To solve for xx, simplify the equation above: 11x+5=13x1511x + 5 = 13x - 15 Subtract 11x11x from both sides: 5=2x155 = 2x - 15 Add 15 to both sides: 20=2x20 = 2x Divide by 2: x=10x = 10

Now that we know x=10x = 10, substitute this into the expression for EFEF: EF=8x+2=8(10)+2=80+2=82EF = 8x + 2 = 8(10) + 2 = 80 + 2 = 82

Final Answers:

  • x=10x = 10
  • EF=82EF = 82

Let me know if you need further explanation, or if you'd like to explore additional details on this problem!

Here are 5 related questions you might find helpful:

  1. What is the relationship between bisectors and midpoint properties in geometry?
  2. Can a line bisect a line segment in more than one point? Why or why not?
  3. How can algebraic methods help in solving geometry problems involving line segments?
  4. What is the difference between a bisector and a perpendicular bisector?
  5. If the equation for EFEF changed, how would it affect the overall solution?

Tip: When you see the term "bisects," always think about equal parts—this is key in setting up equations for geometric problems.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry
Bisectors
Linear Equations

Formulas

CG = GD
EF = 8x + 2

Theorems

Bisector Theorem
Algebraic equation solving

Suitable Grade Level

Grades 8-10