Math Problem Statement

Find GE, where the segment HE is divided into segments: HG = 13x - 993, GF = 3x - 129, FE = 3x - 185, and EF = 4.

Solution

The problem shows a segment HEHE, with points GG and FF between HH and EE. The lengths of different segments along this line are represented by the following algebraic expressions:

  • HG=13x993HG = 13x - 993
  • GF=3x129GF = 3x - 129
  • FE=3x185FE = 3x - 185
  • EF=4EF = 4

To find GEGE, we can express GEGE as the sum of the segments GFGF and FEFE.

So, we have: GE=GF+FEGE = GF + FE Substitute the expressions for GFGF and FEFE: GE=(3x129)+(3x185)GE = (3x - 129) + (3x - 185) Simplifying: GE=3x129+3x185=6x314GE = 3x - 129 + 3x - 185 = 6x - 314

Thus, the length of GEGE is 6x3146x - 314.

Would you like to proceed by solving for xx, or do you want further details on the steps? Here are some follow-up questions:

  1. How do we solve for xx if we know the total length of HEHE?
  2. How can we express the length of HEHE in terms of xx?
  3. What additional steps are needed to solve for GEGE once xx is found?
  4. How does knowing the value of FEFE help solve the problem?
  5. How do you verify the accuracy of the solution?

Tip: When solving problems with segments, always add smaller segments to express the larger segment.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Geometry of Segments

Formulas

GE = GF + FE
GF = 3x - 129
FE = 3x - 185

Theorems

-

Suitable Grade Level

Grades 8-10