Math Problem Statement

Consider the following relation.

y+x‾‾√=−4x+(x−4)2y+x=−4x+(x−4)^2

Step 3 of 3 :  

Determine the implied domain of the function found in the first step. Express your answer in interval notation.

Solution

The given equation is:

y+x=4x+(x4)2y + \sqrt{x} = -4x + (x - 4)^2

Step 1: Solve for yy

We will first isolate yy on one side.

y=4x+(x4)2xy = -4x + (x - 4)^2 - \sqrt{x}

This represents a function y=f(x)y = f(x).

Step 2: Determine the domain of the function

To find the domain, we need to consider the restrictions on xx that come from the square root, as well as any other restrictions.

  • Square Root Restriction: The expression x\sqrt{x} implies that xx must be non-negative because the square root of a negative number is not defined in the real number system. x0x \geq 0

There are no other restrictions in the function, since the rest of the expression consists of polynomials, which are defined for all real numbers.

Step 3: Final Domain

The domain is the set of xx-values for which the function is defined. Since xx must be non-negative, the domain is:

[0,)[0, \infty)

Final Answer:

The domain of the function is [0,)[0, \infty).

Would you like more details or have any questions?


Here are 5 questions to expand on this topic:

  1. How do you handle square roots in function domains?
  2. What happens if a square root is in the denominator?
  3. How do polynomials affect the domain of a function?
  4. What would happen to the domain if we had x3\sqrt{x - 3} instead of x\sqrt{x}?
  5. How do you graph a function with a restricted domain?

Tip: Always check for square roots and denominators when determining the domain of a function.

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions
Domain and Range
Square Roots

Formulas

y = −4x + (x − 4)^2 - sqrt(x)

Theorems

Square Root Domain Restriction

Suitable Grade Level

Grades 9-12