Math Problem Statement

f(x) =

f(x) = √(x + 4) - 2

Solution

The function written in the image is:

f(x)=x+42f(x) = \sqrt{x + 4} - 2

This represents a square root function, where the expression inside the square root is x+4x + 4, and 2 is subtracted from the square root value.

Domain:

For the square root function to be defined, the expression inside the square root must be non-negative: x+40    x4x + 4 \geq 0 \implies x \geq -4 Thus, the domain of f(x)f(x) is x4x \geq -4.

Would you like more details, or do you have any questions?

Here are 5 questions related to this concept:

  1. What is the range of the function f(x)=x+42f(x) = \sqrt{x+4} - 2?
  2. How do we graph the function f(x)=x+42f(x) = \sqrt{x+4} - 2?
  3. How do transformations affect the function f(x)f(x)?
  4. What happens to the domain if we modify the function to f(x)=x+4+2f(x) = \sqrt{x+4} + 2?
  5. Can you find the inverse of the function f(x)=x+42f(x) = \sqrt{x+4} - 2?

Tip: When working with square roots, always remember that the value inside the root must be non-negative to avoid complex numbers.

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Math Problem Analysis

Mathematical Concepts

Algebra
Square Root Functions
Domain and Range

Formulas

f(x) = √(x + 4) - 2
Domain: x + 4 ≥ 0

Theorems

Domain of square root functions

Suitable Grade Level

Grades 9-11