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To find the critical points, maximum, and minimum of the given function \( f(x) = \sin(\sin(x)) + \cos(\cos(x)) \) over the interval \([0, \frac{\pi}{3}]\), we follow these steps:

### 1. Find the derivative of the function \( f'(x) \)
The first step is to differentiate \( f(x) \) with respect to \( x \). We will use the chain rule for both terms.

\[
f'(x) = \frac{d}{dx}[\sin(\sin(x))] + \frac{d}{dx}[\cos(\cos(x))]
\]

For the first term:
\[
\frac{d}{dx}[\sin(\sin(x))] = \cos(\sin(x)) \cdot \cos(x)
\]

For the second term:
\[
\frac{d}{dx}[\cos(\cos(x))] = -\sin(\cos(x)) \cdot (-\sin(x)) = \sin(\cos(x)) \cdot \sin(x)
\]

Thus, the derivative is:
\[
f'(x) = \cos(\sin(x)) \cdot \cos(x) + \sin(\cos(x)) \cdot \sin(x)
\]

### 2. Set the derivative equal to zero
To find the critical points, we set \( f'(x) = 0 \):
\[
\cos(\sin(x)) \cdot \cos(x) + \sin(\cos(x)) \cdot \sin(x) = 0
\]

We need to solve this equation for \( x \) in the interval \([0, \frac{\pi}{3}]\). This might require numerical methods or further analysis depending on complexity, but let's proceed analytically for now.

### 3. Check the endpoints and critical points
Once the critical points are determined, evaluate \( f(x) \) at those points and at the endpoints of the interval, \( x = 0 \) and \( x = \frac{\pi}{3} \), to determine the maximum and minimum.

#### At \( x = 0 \):
\[
f(0) = \sin(\sin(0)) + \cos(\cos(0)) = \sin(0) + \cos(1) = 0 + \cos(1)
\]

#### At \( x = \frac{\pi}{3} \):
\[
f\left(\frac{\pi}{3}\right) = \sin\left(\sin\left(\frac{\pi}{3}\right)\right) + \cos\left(\cos\left(\frac{\pi}{3}\right)\right)
\]
Since \( \sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2} \) and \( \cos\left(\frac{\pi}{3}\right) = \frac{1}{2} \), we can compute:
\[
f\left(\frac{\pi}{3}\right) = \sin\left(\frac{\sqrt{3}}{2}\right) + \cos\left(\frac{1}{2}\right)
\]

### 4. Compare values
Finally, by evaluating \( f(x) \) at these points (including the critical points), we can determine the maximum and minimum values of the function on the interval.

Would you like further details on solving the derivative equation for critical points, or any other part of the problem?

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Here are 5 related questions you might find helpful:
1. How can we numerically solve trigonometric equations for critical points?
2. What is the significance of using the chain rule in trigonometric differentiation?
3. How do you interpret the behavior of a function based on its critical points?
4. How can endpoint analysis help in finding global extrema in a given interval?
5. How does the sine and cosine of trigonometric values behave in specific ranges like \([0, \frac{\pi}{3}]\)?

**Tip:** In many optimization problems involving trigonometric functions, it's often useful to approximate critical points using numerical methods when analytical solutions are challenging.

Cari titik kritis, max dan min untuk f(x) = sin(sin(x)) + cos(cos(x)) di interval [0, π/3].

This problem explores how to find critical points, maxima, and minima of the trigonometric function f(x) = sin(sin(x)) + cos(cos(x)) over the interval [0, π/3]. Learn to apply the chain rule and critical point theorem.

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