Math Problem Statement
find the point of local minimum of f(x)= sin2x , 0<x<pi.
Solution
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Math Problem Analysis
Mathematical Concepts
Calculus
Trigonometry
Derivative
Critical Points
Second Derivative Test
Formulas
f'(x) = 2cos(2x)
f''(x) = -4sin(2x)
Critical point condition: f'(x) = 0
Second derivative test: If f''(x) > 0, local minimum; if f''(x) < 0, local maximum
Theorems
Second Derivative Test
Suitable Grade Level
Grades 11-12
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