Math Problem Statement

suppose f is a differentiable function with f'(x) = 2sin(pix). At what value of x in the interval 1 < x < 2 does f take its absolute maximum? please explain.

Solution

To find the value of xx in the interval 1<x<21 < x < 2 where f(x)f(x) attains its absolute maximum, we proceed by analyzing the behavior of the derivative f(x)=2sin(πx)f'(x) = 2\sin(\pi x).

Step 1: Identify critical points

A critical point occurs where f(x)=0f'(x) = 0. To find these points, set the derivative equal to zero:

f(x)=2sin(πx)=0f'(x) = 2\sin(\pi x) = 0

This simplifies to:

sin(πx)=0\sin(\pi x) = 0

The sine function equals zero at integer multiples of π\pi, i.e., when πx=nπ\pi x = n\pi, where nn is an integer. Thus:

x=nx = n

In the interval 1<x<21 < x < 2, the only integer is x=1x = 1, but since this is not strictly inside the interval, we exclude it. However, we do need to check for points where the derivative changes sign within this interval.

Step 2: Analyze the behavior of f(x)f'(x) in 1<x<21 < x < 2

We will check the sign of f(x)f'(x) in the interval 1<x<21 < x < 2 by evaluating sin(πx)\sin(\pi x) at some representative points.

  • At x=1.5x = 1.5: sin(π×1.5)=sin(3π2)=1\sin(\pi \times 1.5) = \sin\left(\frac{3\pi}{2}\right) = -1 So f(1.5)=2×(1)=2f'(1.5) = 2 \times (-1) = -2, which means the function is decreasing at x=1.5x = 1.5.

Since sin(πx)\sin(\pi x) is negative in the interval 1<x<21 < x < 2 (excluding x=1x = 1), the derivative is negative throughout this interval, indicating that f(x)f(x) is decreasing.

Step 3: Evaluate the endpoints

The function could attain its absolute maximum at the boundary points. To determine this, we check the values of f(x)f(x) at the endpoints of the interval 1<x<21 < x < 2. However, since the function is decreasing in the entire interval, the absolute maximum will occur at the left endpoint of the interval, which is just after x=1x = 1.

Therefore, the absolute maximum of f(x)f(x) in the interval 1<x<21 < x < 2 occurs as xx approaches 1 from the right.

Final Answer:

The absolute maximum occurs as x1+x \to 1^+ in the interval 1<x<21 < x < 2.


Would you like further clarification on any of the steps?

Here are 5 related questions to expand your understanding:

  1. How would the result change if the interval were 0<x<20 < x < 2?
  2. What is the general behavior of the function f(x)f(x) given its derivative?
  3. How would you determine if the maximum is absolute or local based on f(x)f'(x)?
  4. What role do critical points outside the interval play in determining maxima or minima?
  5. How does the periodic nature of sine affect the behavior of the derivative?

Tip: To analyze critical points, always check the derivative's sign changes, as they indicate where a function increases or decreases.

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Math Problem Analysis

Mathematical Concepts

Calculus
Differentiation
Critical Points
Maxima and Minima
Trigonometric Functions

Formulas

f'(x) = 2sin(πx)
sin(πx) = 0 when x = n (where n is an integer)
f'(x) changes sign to indicate maxima or minima

Theorems

First Derivative Test
Critical Points Theorem

Suitable Grade Level

Grades 11-12