Math Problem Statement
suppose f is a differentiable function with f'(x) = 2sin(pix). At what value of x in the interval 1 < x < 2 does f take its absolute maximum? please explain.
Solution
To find the value of in the interval where attains its absolute maximum, we proceed by analyzing the behavior of the derivative .
Step 1: Identify critical points
A critical point occurs where . To find these points, set the derivative equal to zero:
This simplifies to:
The sine function equals zero at integer multiples of , i.e., when , where is an integer. Thus:
In the interval , the only integer is , but since this is not strictly inside the interval, we exclude it. However, we do need to check for points where the derivative changes sign within this interval.
Step 2: Analyze the behavior of in
We will check the sign of in the interval by evaluating at some representative points.
- At : So , which means the function is decreasing at .
Since is negative in the interval (excluding ), the derivative is negative throughout this interval, indicating that is decreasing.
Step 3: Evaluate the endpoints
The function could attain its absolute maximum at the boundary points. To determine this, we check the values of at the endpoints of the interval . However, since the function is decreasing in the entire interval, the absolute maximum will occur at the left endpoint of the interval, which is just after .
Therefore, the absolute maximum of in the interval occurs as approaches 1 from the right.
Final Answer:
The absolute maximum occurs as in the interval .
Would you like further clarification on any of the steps?
Here are 5 related questions to expand your understanding:
- How would the result change if the interval were ?
- What is the general behavior of the function given its derivative?
- How would you determine if the maximum is absolute or local based on ?
- What role do critical points outside the interval play in determining maxima or minima?
- How does the periodic nature of sine affect the behavior of the derivative?
Tip: To analyze critical points, always check the derivative's sign changes, as they indicate where a function increases or decreases.
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Math Problem Analysis
Mathematical Concepts
Calculus
Differentiation
Critical Points
Maxima and Minima
Trigonometric Functions
Formulas
f'(x) = 2sin(πx)
sin(πx) = 0 when x = n (where n is an integer)
f'(x) changes sign to indicate maxima or minima
Theorems
First Derivative Test
Critical Points Theorem
Suitable Grade Level
Grades 11-12
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