The given series is:

$\frac{1}{8}, \frac{1}{4}, \frac{1}{2}, \dots$

This is a geometric sequence where the first term $a_1 = \frac{1}{8}$, and the common ratio $r$ can be found by dividing the second term by the first:

$r = \frac{\frac{1}{4}}{\frac{1}{8}} = 2$

The formula for the $n$-th term of a geometric sequence is:

$a_n = a_1 \cdot r^{n-1}$

To find the 8th term ($a_8$):

$a_8 = \frac{1}{8} \cdot 2^{8-1} = \frac{1}{8} \cdot 2^7 = \frac{1}{8} \cdot 128 = 16$

So, the 8th term of the series is:

$\boxed{16}$

Would you like further details on geometric sequences or have any questions?

Here are 5 related questions for practice:

1. What is the 10th term of the series $2, 4, 8, \dots$?
2. How do you find the sum of the first $n$ terms in a geometric series?
3. What is the common ratio in the sequence $3, 6, 12, \dots$?
4. How do you determine if a sequence is geometric?
5. What is the 6th term of the sequence $5, 15, 45, \dots$?

Tip: When working with geometric sequences, always double-check the common ratio before applying formulas.