Math Problem Statement

6th terms of 3,-6,12,-24

Solution

The given sequence is: 3, -6, 12, -24, ...

This appears to be a geometric sequence, where each term is obtained by multiplying the previous term by a constant ratio.

To find the common ratio rr, divide the second term by the first term: r=63=2r = \frac{-6}{3} = -2 Thus, the common ratio r=2r = -2.

The formula for the nn-th term of a geometric sequence is: an=a1rn1a_n = a_1 \cdot r^{n-1} where a1a_1 is the first term, and rr is the common ratio.

For the 6th term a6a_6: a6=3(2)61=3(2)5=3(32)=96a_6 = 3 \cdot (-2)^{6-1} = 3 \cdot (-2)^5 = 3 \cdot (-32) = -96

So, the 6th term of the sequence is -96.

Would you like further details or have any questions?

Here are 5 related questions:

  1. How do you find the sum of a geometric sequence?
  2. What is the general formula for the sum of the first nn terms of a geometric series?
  3. How does the behavior of a geometric sequence change when the common ratio is less than 1?
  4. What is the significance of the common ratio in a geometric sequence?
  5. Can a geometric sequence have a positive common ratio but alternating signs?

Tip: Always double-check the common ratio when working with sequences to ensure accurate term predictions!

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometric Sequences

Formulas

Geometric sequence formula: a_n = a_1 * r^(n-1)

Theorems

Geometric sequence theorem

Suitable Grade Level

Grades 8-10