Can you explain the steps to perform long subtraction?

Sure, let's go through the steps to perform long subtraction using the example \( 35 - 98 \).

### Step-by-Step Explanation:

1. **Write the numbers in columns:**
   Align the numbers by their place values (ones, tens, etc.).
   ```
     35
   - 98
   ```

2. **Start from the rightmost column (ones place):**
   Subtract the bottom digit from the top digit. If the top digit is smaller than the bottom digit, you need to borrow from the next column to the left.

   Here, 5 (ones place) is smaller than 8. So, we need to borrow from the tens place.

3. **Borrowing:**
   - Borrow 1 from the tens place of 3. This makes the 3 become 2.
   - Add 10 to the 5, making it 15.

   After borrowing:
   ```
      2(10)5
   -  98
   ```

4. **Subtract the ones place:**
   Now subtract 8 from 15:
   ```
   15 - 8 = 7
   ```

5. **Subtract the tens place:**
   Now subtract 9 from 2 (tens place), which was reduced to 2 after borrowing:
   ```
    2 - 9 = -7
   ```

Since subtracting a larger digit from a smaller one in the tens place results in a negative number, we combine the two parts:
```
-7 (tens) + 7 (ones) = -63
```

### Putting it together:
Thus, \( 35 - 98 = -63 \).

Would you like more details or have any questions about this process? Here are five questions you can ask:

1. How do you perform subtraction with multiple borrowings?
2. What is the difference between borrowing and carrying in arithmetic?
3. Can you demonstrate long subtraction with larger numbers?
4. How does borrowing work in other bases, like binary or hexadecimal?
5. How can I check my subtraction work for accuracy?

**Tip:** Always ensure you align numbers by their place values when performing long subtraction to avoid errors.

Learn how to perform long subtraction step-by-step with an example of 35 - 98. This problem covers subtraction, borrowing, and aligning numbers by their place values. Suitable for students in Grades 3-5.

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