Math Problem Statement

Solution

To solve this problem, let's break it down into steps and use the properties of hyperbolas.

Given Information:

The hyperbola is defined by: x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 with foci F1F_1 and F2F_2.

Focus Points:

For a hyperbola, the foci are located at: F1=(c,0)F_1 = (-c, 0) F2=(c,0)F_2 = (c, 0) where c=a2+b2c = \sqrt{a^2 + b^2}.

Line Passing through F2F_2 Parallel to the y-axis:

This line intersects the hyperbola at points AA and BB.

Given Distances:

F1A=13|F_1A| = 13 AB=10|AB| = 10

We need to find the distance of point CC from the center.

Steps to Solve:

  1. Determine the foci coordinates F1F_1 and F2F_2: c=a2+b2c = \sqrt{a^2 + b^2}

  2. Find the coordinates of AA and BB: Since the line passing through F2F_2 is parallel to the y-axis, we can write the equations as: x=cx = c

    Substitute x=cx = c into the hyperbola equation: c2a2y2b2=1\frac{c^2}{a^2} - \frac{y^2}{b^2} = 1 y2b2=c2a21\frac{y^2}{b^2} = \frac{c^2}{a^2} - 1 y2=b2(c2a2a2)y^2 = b^2 \left( \frac{c^2 - a^2}{a^2} \right) y2=b2(b2a2)y^2 = b^2 \left( \frac{b^2}{a^2} \right) y2=b4a2y^2 = \frac{b^4}{a^2} y=±b2ay = \pm \frac{b^2}{a}

    So the coordinates of AA and BB are: A=(c,b2a)A = (c, \frac{b^2}{a}) B=(c,b2a)B = (c, -\frac{b^2}{a})

  3. Distance Calculation: Given F1A=13|F_1A| = 13: F1A=(c+c)2+(b2a)2=13|F_1A| = \sqrt{(c + c)^2 + \left(\frac{b^2}{a}\right)^2} = 13 F1A=4c2+b4a2=13|F_1A| = \sqrt{4c^2 + \frac{b^4}{a^2}} = 13 4c2+b4a2=1694c^2 + \frac{b^4}{a^2} = 169

  4. Finding ABAB: Given AB=10|AB| = 10: AB=2b2a=10|AB| = \left|\frac{2b^2}{a}\right| = 10 2b2a=10\frac{2b^2}{a} = 10 b2=5ab^2 = 5a

  5. Substitute b2b^2 into the first equation: b4=(5a)2=25a2b^4 = (5a)^2 = 25a^2 4c2+25a2a2=1694c^2 + \frac{25a^2}{a^2} = 169 4c2+25=1694c^2 + 25 = 169 4c2=1444c^2 = 144 c2=36c^2 = 36 c=6c = 6

Finding the distance of CC from the center:

Given that c=6c = 6 and CC is located at (c,0)(c, 0), the distance of CC from the center (origin) is: OC=6|OC| = 6

So, the distance of point CC from the center is: 6\boxed{6}

Do you want any further details or have any other questions?

Here are 5 questions you might ask:

  1. How do we derive the equations of a hyperbola's asymptotes?
  2. Can you explain how to find the eccentricity of a hyperbola?
  3. How do the distances between the foci and vertices relate to the hyperbola's properties?
  4. How can we determine the equations of lines tangent to a hyperbola?
  5. How do hyperbolas differ from other conic sections in terms of their geometric properties?

Tip: When dealing with hyperbolas and their properties, remember to leverage the relationship between the semi-major axis, semi-minor axis, and the distance to the foci, which provides a clear geometric framework for solving related problems.

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Math Problem Analysis

Mathematical Concepts

Hyperbolas
Coordinate Geometry
Geometry of Conic Sections

Formulas

Equation of a hyperbola: x^2/a^2 - y^2/b^2 = 1
Foci of a hyperbola: F1 = (-c, 0), F2 = (c, 0), where c = sqrt(a^2 + b^2)
Distance relation for hyperbola: |F1A| = sqrt((c + c)^2 + (b^2/a)^2)
Distance |AB| = 2b^2/a

Theorems

Properties of Hyperbolas
Distance Formula
Equation of a Hyperbola

Suitable Grade Level

Grades 10-12