Math Problem Statement
In Exercises 1-3, evaluate the arithmetic series. Using the formula an=a1+(n−1)d.
-
1 + 2 + 3 +***+98+99+100
-
500 + 490 + 480 +***+320+310+300
-
2001 + 2002 + 2003 +***+4998+4999+5000
Solution
We will use the formula for the -th term of an arithmetic series:
where:
- is the -th term,
- is the first term,
- is the common difference, and
- is the number of terms.
To find the sum of the arithmetic series, we also use the sum formula:
where:
- is the sum of the first terms,
- is the first term,
- is the last term,
- is the number of terms.
1.
For this arithmetic series:
- First term, ,
- Last term, ,
- Common difference, .
Now, the number of terms is 100. Using the sum formula:
So, the sum is 5050.
2.
For this arithmetic series:
- First term, ,
- Last term, ,
- Common difference, .
Now, we find the number of terms . Using the formula for the -th term:
Now, we can calculate the sum:
So, the sum is 8400.
3.
For this arithmetic series:
- First term, ,
- Last term, ,
- Common difference, .
Now, we find the number of terms . Using the formula for the -th term:
Now, we can calculate the sum:
So, the sum is 10,501,500.
Would you like more details or have any questions? Here are some related problems you can try:
- What is the sum of the series ?
- Evaluate the sum of .
- What is the sum of the first 50 terms of the series ?
- Find the sum of .
- Calculate the sum of .
Tip: For any arithmetic sequence, always check the common difference before applying the formulas.
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Math Problem Analysis
Mathematical Concepts
Arithmetic Series
Algebra
Summation
Formulas
nth term formula: an = a1 + (n−1)d
Sum formula: Sn = (n/2) * (a1 + an)
Theorems
Arithmetic Series Theorem
Suitable Grade Level
Grades 8-10