Math Problem Statement

2+6+12+20+30+42 find the sum of 50 terms

Solution

The given sequence is:

2,6,12,20,30,42,2, 6, 12, 20, 30, 42, \dots

First, let's analyze the pattern in the sequence. The difference between consecutive terms forms another sequence:

62=4,126=6,2012=8,3020=10,4230=126 - 2 = 4,\quad 12 - 6 = 6,\quad 20 - 12 = 8,\quad 30 - 20 = 10,\quad 42 - 30 = 12

This shows that the sequence of differences is 4,6,8,10,12,4, 6, 8, 10, 12, \dots, which is an arithmetic sequence with a first term of 4 and a common difference of 2.

Now, we can express the nnth term of the original sequence as:

an=2+(2+4+6++(2n2))a_n = 2 + (2 + 4 + 6 + \dots + (2n - 2))

This sequence 2+4+6++(2n2)2 + 4 + 6 + \dots + (2n - 2) is itself an arithmetic series where:

  • First term: 22
  • Common difference: 22
  • Number of terms: n1n-1

The sum of the first n1n-1 terms of this arithmetic sequence can be found using the formula:

Sn1=(n1)2×(first term + last term)=(n1)2×(2+2(n1))S_{n-1} = \frac{(n-1)}{2} \times \text{(first term + last term)} = \frac{(n-1)}{2} \times \left(2 + 2(n-1)\right)

Simplifying the expression:

Sn1=(n1)×(n)S_{n-1} = (n-1) \times (n)

Thus, the nnth term of the sequence ana_n is:

an=2+Sn1=2+n(n1)a_n = 2 + S_{n-1} = 2 + n(n-1)

Simplifying further:

an=n2+na_n = n^2 + n

Now, to find the sum of the first 50 terms, we use the sum formula for an arithmetic series:

S50=n=150an=n=150(n2+n)S_{50} = \sum_{n=1}^{50} a_n = \sum_{n=1}^{50} (n^2 + n)

This can be split into two sums:

S50=n=150n2+n=150nS_{50} = \sum_{n=1}^{50} n^2 + \sum_{n=1}^{50} n

Using the sum formulas:

n=150n2=50×51×1016=42925\sum_{n=1}^{50} n^2 = \frac{50 \times 51 \times 101}{6} = 42925 n=150n=50×512=1275\sum_{n=1}^{50} n = \frac{50 \times 51}{2} = 1275

Adding them together gives:

S50=42925+1275=44200S_{50} = 42925 + 1275 = 44200

So, the sum of the first 50 terms of the sequence is 44,200.

Would you like any details or have any questions?

Here are 5 related questions to explore:

  1. What is the sum of the first 100 terms of this sequence?
  2. How would you find the nnth term if the sequence had a different pattern of differences?
  3. Can you generalize the formula for the sum of any arithmetic sequence?
  4. What is the sum of squares of the first 50 natural numbers?
  5. How does this method change if the sequence was geometric instead of arithmetic?

Tip: When dealing with sequences, look for patterns in differences to determine the type and formula for the sequence.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Arithmetic Series
Summation Formulas

Formulas

Sum of squares formula
Sum of arithmetic series formula

Theorems

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Suitable Grade Level

Grades 10-12