Math Problem Statement

y Ω (x + y + z) 3/2 dx dy dz, where Ω is defined as x 2 + y 2 + z 2 ≤ 12, x2 + y 2 ≤ 4z.

Solution

To evaluate the integral

Ω(x+y+z)3/2dxdydz,\int_{\Omega} (x + y + z)^{3/2} \, dx \, dy \, dz,

where Ω\Omega is defined by the constraints:

  1. x2+y2+z212x^2 + y^2 + z^2 \leq 12 (a sphere of radius 12\sqrt{12}),
  2. x2+y24zx^2 + y^2 \leq 4z (a paraboloid),

we need to carefully analyze the region and use an appropriate coordinate system for simplification. A spherical or cylindrical coordinate system is likely useful here. Here's how to proceed:


Step 1: Analyze the Region Ω\Omega

  • The sphere x2+y2+z2=12x^2 + y^2 + z^2 = 12 has a radius of 12=23\sqrt{12} = 2\sqrt{3} and is centered at the origin.
  • The paraboloid x2+y2=4zx^2 + y^2 = 4z opens upwards and intersects the sphere to define the upper boundary.

Step 2: Convert to Spherical Coordinates

In spherical coordinates:

  • x=ρsinϕcosθx = \rho \sin\phi \cos\theta,
  • y=ρsinϕsinθy = \rho \sin\phi \sin\theta,
  • z=ρcosϕz = \rho \cos\phi,
  • The volume element is dV=ρ2sinϕdρdϕdθdV = \rho^2 \sin\phi \, d\rho \, d\phi \, d\theta.

Transform the boundaries:

  1. x2+y2+z212x^2 + y^2 + z^2 \leq 12 becomes ρ23\rho \leq 2\sqrt{3},
  2. x2+y24zx^2 + y^2 \leq 4z in spherical coordinates is ρ2sin2ϕ4ρcosϕ\rho^2 \sin^2\phi \leq 4\rho\cos\phi, simplifying to ρsin2ϕ4cosϕ\rho \sin^2\phi \leq 4\cos\phi.

This gives the effective constraint for ϕ\phi: sin2ϕ4ρcosϕ.\sin^2\phi \leq \frac{4}{\rho}\cos\phi.


Step 3: Set Up the Integral in Spherical Coordinates

The integral becomes: 02π0ϕmax023(ρsinϕcosθ+ρsinϕsinθ+ρcosϕ)3/2ρ2sinϕdρdϕdθ,\int_0^{2\pi} \int_0^{\phi_{\max}} \int_0^{2\sqrt{3}} (\rho \sin\phi \cos\theta + \rho \sin\phi \sin\theta + \rho \cos\phi)^{3/2} \rho^2 \sin\phi \, d\rho \, d\phi \, d\theta, where ϕmax\phi_{\max} depends on the intersection of the paraboloid and sphere.


Step 4: Simplify and Compute (if feasible)

The angular dependence and the limits may require numerical evaluation. If you’re solving this manually, simplify the expression by:

  • Splitting into symmetric components,
  • Computing each term individually using symmetry,
  • Substituting bounds explicitly.

Do you want me to compute this numerically or proceed analytically for detailed evaluation?


Relative Questions

  1. How do spherical coordinates simplify integrals over regions bounded by spheres or paraboloids?
  2. Can the symmetry of the region reduce the complexity of this integral?
  3. How do we determine the intersection of a sphere and a paraboloid?
  4. What are typical strategies for evaluating integrals with (x+y+z)3/2(x + y + z)^{3/2}-type expressions?
  5. How does the volume element ρ2sinϕdρdϕdθ\rho^2 \sin\phi \, d\rho \, d\phi \, d\theta come into play in spherical coordinates?

Tip: Always visualize the intersection of 3D regions to better understand

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Spherical Coordinates
Integration over a Region
Volume Integrals

Formulas

Volume element in spherical coordinates: dV = ρ^2 sin(φ) dρ dφ dθ
Coordinate transformations: x = ρ sin(φ) cos(θ), y = ρ sin(φ) sin(θ), z = ρ cos(φ)

Theorems

Fubini's Theorem
Symmetry in Integration
Spherical Coordinate Transformations

Suitable Grade Level

Undergraduate (Calculus II/III)