Math Problem Statement

If f(x) = x^2 + x - 6 and g(x) = (x - 2) / (x + 3), then f(g(2))?

Solution

Let's solve the given problem step by step.

We are given two functions:

  1. f(x)=x2+x6f(x) = x^2 + x - 6
  2. g(x)=x2x+3g(x) = \frac{x - 2}{x + 3}

We are tasked with finding f(g(2))f(g(2)).

Step 1: Compute g(2)g(2)

Using the definition of g(x)g(x), substitute x=2x = 2:

g(2)=222+3=05=0g(2) = \frac{2 - 2}{2 + 3} = \frac{0}{5} = 0

So, g(2)=0g(2) = 0.

Step 2: Compute f(g(2))=f(0)f(g(2)) = f(0)

Now that we know g(2)=0g(2) = 0, we substitute x=0x = 0 into the function f(x)f(x):

f(0)=02+06=6f(0) = 0^2 + 0 - 6 = -6

Therefore, f(g(2))=6f(g(2)) = -6.

Final Answer:

The value of f(g(2))f(g(2)) is 6-6, so the correct option is 6-6.

Would you like more details on any part of this solution?

Here are 5 related questions to expand your understanding:

  1. What happens if g(x)g(x) has a denominator that can cause division by zero?
  2. Can we generalize this process for different functions f(x)f(x) and g(x)g(x)?
  3. What is the domain of the composite function f(g(x))f(g(x))?
  4. How do we differentiate f(g(x))f(g(x)) if both functions are differentiable?
  5. What is the importance of the order in which we apply functions in composition?

Tip: When working with function compositions, always check the domain of each function to avoid undefined values.

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Math Problem Analysis

Mathematical Concepts

Algebra
Function Composition
Quadratic Equations
Rational Functions

Formulas

f(x) = x^2 + x - 6
g(x) = (x - 2) / (x + 3)
f(g(2)) = f(0)
f(0) = 0^2 + 0 - 6

Theorems

Function Composition Theorem

Suitable Grade Level

Grades 9-11