In the image, the problem asks you to evaluate a function given two expressions: $f(x) = x + 3$ and $g(x) = x^2 - 2$. The specific task is to find $(f \circ g)(6)$, which means to evaluate the composite function $f(g(6))$.

Let’s solve it step by step:

1. First, find $g(6)$: $g(x) = x^2 - 2$ Plugging in $x = 6$: $g(6) = 6^2 - 2 = 36 - 2 = 34$

2. Now, use this result in the function $f(x)$, where $x = g(6) = 34$: $f(x) = x + 3$ Plugging in $x = 34$: $f(34) = 34 + 3 = 37$

So, $(f \circ g)(6) = 37$.

It seems that the answer provided was incorrect (it showed 34 instead of 37).

Would you like further details or clarification?

Here are 5 related questions to deepen your understanding:

1. How would you evaluate $(g \circ f)(6)$?
2. What is the domain of $f(x)$ and $g(x)$?
3. Can you explain the concept of function composition?
4. How would you graph $f(x)$ and $g(x)$ together?
5. What happens if we switch the order of the functions in composition?

Tip: Always remember to evaluate the inner function first when working with composite functions.