The given expression is:

\[
25(2^{\log}) = x
\]

There seems to be a small ambiguity, but I'll assume that you're referring to the following interpretation:

\[
25 \times (2^{\log{2}}) = x
\]

where \(\log{2}\) represents the logarithm base 10 of 2. Let's go step by step:

1. We know that \( \log{2} \approx 0.3010 \), so:

\[
2^{\log{2}} = 2^{0.3010} \approx 1.2311
\]

2. Now, multiply 25 by \(1.2311\):

\[
25 \times 1.2311 \approx 30.7775
\]

Thus, the value of \(x\) is approximately:

\[
x \approx 30.78
\]

Would you like more details on logarithms or exponentiation?

Here are 5 related questions:
1. What is the difference between \(\log\) (base 10) and \(\ln\) (natural logarithm)?
2. How do logarithmic and exponential functions relate to each other?
3. Can logarithmic functions have negative results?
4. How do we solve equations involving logarithms of different bases?
5. What are the common properties of logarithms and exponents?

**Tip**: When working with logarithmic and exponential expressions, always clarify the base of the logarithm, as different bases (e.g., base 10 or base \(e\)) can lead to different results.

Explore the step-by-step solution of the expression 25(2^log), which involves understanding the relationship between logarithms and exponents. This solution uses the approximate value of log base 10 of 2 and multiplication techniques, suitable for students in Grades 9-12.

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