https://file.aiquickdraw.com/mathbot/file/1728051655180kg33uesc.jpg

The problem shown in the image is:

**Given:**  
\[ 2x^2 - 3xy \]
with values \( x = -2 \) and \( y = 1 \).

Let's solve this step by step:

### Step 1: Substitute the values of \( x \) and \( y \).
\[
2(-2)^2 - 3(-2)(1)
\]

### Step 2: Simplify the terms.
- First, calculate \( (-2)^2 = 4 \).
\[
2(4) - 3(-2)(1)
\]
- Now, simplify \( 2(4) = 8 \) and \( -3(-2) = 6 \).
\[
8 + 6
\]

### Step 3: Final result.
\[
8 + 6 = 14
\]

So, the value of the expression \( 2x^2 - 3xy \) when \( x = -2 \) and \( y = 1 \) is **14**.

Do you want more details on any step or have any questions?

Here are 5 related questions to expand your understanding:
1. What would the result be if \( x = 3 \) and \( y = -1 \)?
2. How does changing the value of \( y \) affect the expression?
3. Can you rewrite the expression in factorized form?
4. What happens if both \( x \) and \( y \) are negative?
5. How would the solution change if the expression were \( 2x^2 + 3xy \) instead?

**Tip:** Always simplify exponents and multiplications first before performing addition and subtraction when evaluating expressions.

Show the steps & evaluate the given expression: 2x^2 - 3xy. If x = -2 and y = 1

Learn how to solve the algebraic expression 2x^2 - 3xy by substituting values of x = -2 and y = 1. This problem involves algebraic concepts such as substitution and quadratic expressions, suitable for students in Grade 7.

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