Given the values $x = 3$ and $y = -2$, the expression provided is:

$xy^2 - 2x$

Let's substitute the values into the expression:

1. First, calculate $xy^2$: $xy^2 = 3 \times (-2)^2 = 3 \times 4 = 12$

2. Now, calculate $-2x$: $-2x = -2 \times 3 = -6$

3. Finally, subtract the two results: $xy^2 - 2x = 12 - 6 = 6$

So, the value of the expression $xy^2 - 2x$ is $\boxed{6}$.

Would you like more details or have any questions?

Here are 5 related questions to expand on this:

1. What would be the result if $x = 4$ and $y = -3$?
2. How does the expression change if we have $x = 3$ and $y = 0$?
3. Can you find the value of the expression for $x = -2$ and $y = 1$?
4. How does the degree of the polynomial affect the result?
5. What happens if the coefficients in the polynomial are changed?

Tip: When substituting values into an expression, always remember to handle negative signs carefully, especially when squaring negative numbers.