Math Problem Statement

Let A = {1,2,3,4,5,6} and let R be a relation on A defined as follows: m R n ⟺ 2 | (m + n) for all m, n ∈ A. (a) Draw the directed graph of R. (b) Find the equivalence class [5]_R. (c) How many distinct equivalence classes does the relation R have?

Solution

Let's go through each part of this problem, step-by-step.

Given Information:

  • Set A={1,2,3,4,5,6}A = \{1, 2, 3, 4, 5, 6\}.
  • Relation RR on AA is defined such that mRnmRn if and only if 2(m+n)2 \mid (m + n), which means that m+nm + n is even.

Solution:

  1. (a) Directed Graph of RR: To construct the directed graph, we need to determine which pairs (m,n)(m, n) satisfy the relation RR.

    • For two elements m,nAm, n \in A, the sum m+nm + n is even if both mm and nn are either both even or both odd.
    • Even numbers in AA: 2,4,62, 4, 6
    • Odd numbers in AA: 1,3,51, 3, 5

    Therefore:

    • mRnmRn holds for pairs (m,n)(m, n) where both mm and nn are either even or both are odd.

    Pairs that satisfy RR:

    • For odd elements {1,3,5}\{1, 3, 5\}: pairs are (1,1),(1,3),(1,5),(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)(1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), (5,5).
    • For even elements {2,4,6}\{2, 4, 6\}: pairs are (2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)(2,2), (2,4), (2,6), (4,2), (4,4), (4,6), (6,2), (6,4), (6,6).

    Using these pairs, you can create a directed graph with nodes labeled 11 to 66 and arrows connecting nodes according to the pairs above.

  2. (b) Equivalence Class [5]R[5]_R: The equivalence class [5]R[5]_R consists of all elements nAn \in A such that 5Rn5Rn.

    Since 55 is odd, we need to find all odd elements in AA. These are 1,3,1, 3, and 55.

    Thus, [5]R={1,3,5}[5]_R = \{1, 3, 5\}.

  3. (c) Number of Distinct Equivalence Classes: We observe that RR groups elements into two classes based on parity:

    • Odd elements: {1,3,5}\{1, 3, 5\}
    • Even elements: {2,4,6}\{2, 4, 6\}

    These two groups represent two distinct equivalence classes under RR.

    Therefore, the relation RR has 2 distinct equivalence classes.


Would you like further details on any part of the solution?

Related Questions

  1. What makes a relation an equivalence relation, and how can you check it?
  2. How do you interpret equivalence classes in terms of partitions of a set?
  3. How would the solution change if AA had a different number of elements?
  4. Can you find equivalence classes in non-numeric sets, such as sets of words or other objects?
  5. How would you generalize this relation for any finite set AA with an arbitrary rule for even sums?

Tip

To verify that a relation is an equivalence relation, always check that it is reflexive, symmetric, and transitive. These properties are essential for defining equivalence classes.

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Math Problem Analysis

Mathematical Concepts

Relations
Equivalence Relations
Directed Graphs
Equivalence Classes

Formulas

m R n ⟺ 2 | (m + n)

Theorems

Properties of Equivalence Relations (Reflexive, Symmetric, Transitive)

Suitable Grade Level

Grades 10-12