Math Problem Statement

A = {1, 2, 3} and R be the relation defined as R = {(1, 1), (1, 2), (2, 2), (2, 3), (3, 3)} Is R equivalence?

Solution

To determine whether the relation R={(1,1),(1,2),(2,2),(2,3),(3,3)}R = \{(1,1), (1,2), (2,2), (2,3), (3,3)\} is an equivalence relation on the set A={1,2,3}A = \{1, 2, 3\}, we need to check if RR satisfies the three properties of an equivalence relation: reflexivity, symmetry, and transitivity.

1. Reflexivity:

A relation RR on a set AA is reflexive if every element in AA is related to itself, i.e., for all aAa \in A, (a,a)R(a, a) \in R.

For A={1,2,3}A = \{1, 2, 3\}, we need the pairs (1,1),(2,2),(3,3)(1, 1), (2, 2), (3, 3) to be in RR.

  • (1,1)R(1, 1) \in R, which is true.
  • (2,2)R(2, 2) \in R, which is true.
  • (3,3)R(3, 3) \in R, which is true.

Since all elements of AA are related to themselves, the relation RR is reflexive.

2. Symmetry:

A relation RR on a set AA is symmetric if for all a,bAa, b \in A, whenever (a,b)R(a, b) \in R, it must also hold that (b,a)R(b, a) \in R.

Check the pairs in RR:

  • (1,1)(1, 1) is symmetric (since (1,1)=(1,1)(1, 1) = (1, 1)).
  • (1,2)R(1, 2) \in R, but (2,1)R(2, 1) \notin R, so symmetry is violated.
  • (2,2)(2, 2) is symmetric.
  • (2,3)R(2, 3) \in R, but (3,2)R(3, 2) \notin R, so symmetry is violated.
  • (3,3)(3, 3) is symmetric.

Since symmetry is violated (for (1,2)(1, 2) and (2,3)(2, 3)), the relation RR is not symmetric.

3. Transitivity:

A relation RR on a set AA is transitive if for all a,b,cAa, b, c \in A, whenever (a,b)R(a, b) \in R and (b,c)R(b, c) \in R, it must also hold that (a,c)R(a, c) \in R.

Check the transitive property for the pairs in RR:

  • (1,1)R(1, 1) \in R and (1,2)R(1, 2) \in R. We need (1,2)R(1, 2) \in R, which is true.
  • (1,2)R(1, 2) \in R and (2,3)R(2, 3) \in R. We need (1,3)R(1, 3) \in R, but (1,3)R(1, 3) \notin R, so transitivity is violated.
  • (2,2)R(2, 2) \in R and (2,3)R(2, 3) \in R. We need (2,3)R(2, 3) \in R, which is true.
  • (3,3)R(3, 3) \in R, so no transitivity check is needed here.

Since the transitivity condition is violated (for (1,2)(1, 2) and (2,3)(2, 3)), the relation RR is not transitive.

Conclusion:

Since the relation RR is reflexive but neither symmetric nor transitive, it is not an equivalence relation.

Would you like more details on any of the properties or steps?


Here are 5 questions to consider based on this topic:

  1. What conditions must a relation satisfy to be transitive?
  2. How does the lack of symmetry impact a relation in practical scenarios?
  3. Can a relation be reflexive but still not an equivalence relation? Why or why not?
  4. What changes could be made to the relation RR to make it symmetric?
  5. How is the concept of equivalence relations applied in real-world mathematical problems?

Tip: When checking if a relation is symmetric, always verify that if (a,b)(a, b) is in the relation, then (b,a)(b, a) must also be in the relation.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Set Theory
Relations
Equivalence Relations

Formulas

-

Theorems

Equivalence Relation Theorem

Suitable Grade Level

Grades 9-12