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In the problem, you have an equilateral triangle where each side length is given as \(x + 3\) and the perimeter is 48. We need to solve for \(x\).

Since an equilateral triangle has all sides equal, we know the perimeter \(P\) is given by:
\[
P = 3 \times \text{side length}
\]
Setting the perimeter to 48, we have:
\[
3(x + 3) = 48
\]
Now we can solve for \(x\):
\[
3x + 9 = 48
\]
\[
3x = 48 - 9
\]
\[
3x = 39
\]
\[
x = \frac{39}{3}
\]
\[
x = 13
\]

Thus, \(x = 13\).

Would you like to explore any related topics or have further questions on this solution?

Here are a few suggestions:
1. How would the solution change if the perimeter was different?
2. Can we use this method to solve for the side lengths of other polygon types?
3. How does changing the expression for the side length affect the perimeter?
4. What is the area of this equilateral triangle with side length \(x + 3\)?
5. Could you explain how the distributive property works in equations like these?

Tip: When dealing with geometric problems, it can be helpful to draw a diagram to better visualize the scenario.

Given that the side length of the equilateral triangle below is x + 3 and its perimeter is 48, solve for x.

Learn how to solve for x in an equilateral triangle where the side length is expressed as x + 3 and the perimeter is 48. This problem involves basic algebra and geometric properties of triangles, suitable for students in Grades 7-9.

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